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Top Forums UNIX for Beginners Questions & Answers Min/max/total for selected columns based on first column as ID Post 303045489 by jiam912 on Friday 27th of March 2020 02:23:58 PM
Old 03-27-2020
Min/max/total for selected columns based on first column as ID

For every ID in column one, I want to get the min/max/total for each ID.


The values in different columns are not sorted, the actual attempt, works only if the columns are sorted.


input file
Code:
2010  1  44413               41105.0 21.75 146  
2010  1  44415               41105.0 21.75 146  
2010  1  44417               41105.0 21.75 100  
2010  1  44419               41105.0 28.00 146 
2010  1  50000               41105.0 21.75 200  
2010  1  44423               41105.0 21.75 146  
2011  1  44425               41105.0 21.75 146  
2011  1  44427               41105.0 20.00 146  
2011  1  70000               41105.0 21.75 146  
2011  1  44433               41105.0 29.00 700  
2011  1  44435               41105.0 21.00 146  
2012  1  44437               41105.0 21.75 146  
2012  1  20000               41105.0 21.75 150  
2012  1  44441               41105.0 21.75 146  
2012  1  90000               41105.0 21.75 146  
2012  1  44445               41105.0 21.75 600  
2012  1  44447               41105.0 21.75 146  
2012  1  44447               41105.0 21.75 146

attempt

Code:
 awk '{ currKey = $1 }
    currKey != prevKey { prt(); min=$3;min1=$5;min2=$6;cnt=0}
    { prevRec=$0; prevKey=currKey; max=$3;max1=$10;max2=$6; cnt++ }
      { prevKey=currKey; TOTAL+=$6}    
    END { prt() }
    function prt(   f) {
        if ( cnt ) {
        split(prevRec,f)
        print f[1],min,max,min1,max1,min2,max2,TOTAL, cnt
        }
    }' file | column -t

output from attempt
Code:
2010  44413  44423  21.75  21.75  146  146  884   6
2011  44425  44435  21.75  21.00  146  146  2668  5
2012  44437  44447  21.75  21.75  146  146  4002  7

output desired
Code:
2010  44413  50000  21.75  28.00  100  200  884   6
2011  44425  70000  20.00  29.00  146  700  1284  5
2012  20000  90000  21.75  21.75  146  600  1280  7

Appreciate your support

Last edited by jiam912; 03-27-2020 at 07:14 PM..
 

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stbtrs.f(3)							      LAPACK							       stbtrs.f(3)

NAME
stbtrs.f - SYNOPSIS
Functions/Subroutines subroutine stbtrs (UPLO, TRANS, DIAG, N, KD, NRHS, AB, LDAB, B, LDB, INFO) STBTRS Function/Subroutine Documentation subroutine stbtrs (characterUPLO, characterTRANS, characterDIAG, integerN, integerKD, integerNRHS, real, dimension( ldab, * )AB, integerLDAB, real, dimension( ldb, * )B, integerLDB, integerINFO) STBTRS Purpose: STBTRS solves a triangular system of the form A * X = B or A**T * X = B, where A is a triangular band matrix of order N, and B is an N-by NRHS matrix. A check is made to verify that A is nonsingular. Parameters: UPLO UPLO is CHARACTER*1 = 'U': A is upper triangular; = 'L': A is lower triangular. TRANS TRANS is CHARACTER*1 Specifies the form the system of equations: = 'N': A * X = B (No transpose) = 'T': A**T * X = B (Transpose) = 'C': A**H * X = B (Conjugate transpose = Transpose) DIAG DIAG is CHARACTER*1 = 'N': A is non-unit triangular; = 'U': A is unit triangular. N N is INTEGER The order of the matrix A. N >= 0. KD KD is INTEGER The number of superdiagonals or subdiagonals of the triangular band matrix A. KD >= 0. NRHS NRHS is INTEGER The number of right hand sides, i.e., the number of columns of the matrix B. NRHS >= 0. AB AB is REAL array, dimension (LDAB,N) The upper or lower triangular band matrix A, stored in the first kd+1 rows of AB. The j-th column of A is stored in the j-th column of the array AB as follows: if UPLO = 'U', AB(kd+1+i-j,j) = A(i,j) for max(1,j-kd)<=i<=j; if UPLO = 'L', AB(1+i-j,j) = A(i,j) for j<=i<=min(n,j+kd). If DIAG = 'U', the diagonal elements of A are not referenced and are assumed to be 1. LDAB LDAB is INTEGER The leading dimension of the array AB. LDAB >= KD+1. B B is REAL array, dimension (LDB,NRHS) On entry, the right hand side matrix B. On exit, if INFO = 0, the solution matrix X. LDB LDB is INTEGER The leading dimension of the array B. LDB >= max(1,N). INFO INFO is INTEGER = 0: successful exit < 0: if INFO = -i, the i-th argument had an illegal value > 0: if INFO = i, the i-th diagonal element of A is zero, indicating that the matrix is singular and the solutions X have not been computed. Author: Univ. of Tennessee Univ. of California Berkeley Univ. of Colorado Denver NAG Ltd. Date: November 2011 Definition at line 146 of file stbtrs.f. Author Generated automatically by Doxygen for LAPACK from the source code. Version 3.4.2 Tue Sep 25 2012 stbtrs.f(3)
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