Hello all,
I want to create a script that polls every hour a directory for the existence of a file. The file I look for is a `token` dropped by an external process at the completion of a successful FTP process. I wrote this script `checkfile.ksh`:
#!/usr/bin/ksh
if ] then
mailx... (5 Replies)
Hi,
i am getting following syntax error ...kingly advice why is it coming ??
#!/bin/bash
find . -name "common.log"
if ; then
echo "1"
fi
Himnashu@home /bin
$ ./a.sh
./a.sh: line 7: syntax error near unexpected token `fi'
./a.sh: line 7: `fi' (9 Replies)
Hi all,
Am very new to Unix and am currently Involved in Migrating some Shell Scripts from AIX 4 to Solaris 10.
While using teh for loop am getting the below error:
$ echo $SHELL
/usr/bin/ksh
$ for file in $(ls *SEBE*)
syntax error: `$' unexpected
while the same works without issue on... (4 Replies)
So I am trying to convert my bash script into ksh, and this is what I have in the file so far:
#!/bin/ksh
login()
{
if
then
sendcmd BETA
else
sendcmd "$(xxd -c 32 -g 0 ${ZETA_ZETA} | awk '{print $2}')"
fi
}
But when I run it:
$ ./test.sh ... (1 Reply)
unzip file.zip
if ] ; then
echo "Success"
else
echo "Some failure."
fi ;
I tried many time to detect the unzip error, but it keep show the syntax error wherever how I change the syntac. Hope someone can help me fix the issue, thanks.
Please use code tags next time for your code and... (5 Replies)
I have written this in my script but while running i am getting syntax error `(' unexpected.
unload to "$BACKUP_DIR/n_fac_fid-$clliname" select * from n_fac_fid where fac_accesskey in (select fac_accesskey From n_fac_ap_fid where ap_clli="$clliname");
Any help appreciated. (3 Replies)
Dears,
While executing the below script im getting the error at line 30. Please let me know what changes to be done to fix this.
test.sh: line 30: syntax error near unexpected token `done'
test.sh: line 30: ` done '
#!/bin/sh
# Rev. PA1
# author: eillops
# date: 26-04-2018
#
#... (1 Reply)
I am getting this error Syntax error: `]' unexpected. Did I do something wrong with elif? Does ksh not like double brackets?
if ]; then
#echo hi
source ~/.bashrc;
elif ]; then
#echo hi
source ~/.kshrc;
fi (5 Replies)
I've been trying to figure this issue for almost 2 hours now...
I dont see/find any typos or other code mismatches.. but maybe i'm looking at the wrong places....
Here's the console output:
$ LC_ALL=C
$ cd prjs/SWARM/ ; time source ./rc
bash: cd: prjs/SWARM/: No such file or directory... (3 Replies)
Discussion started by: sea
3 Replies
LEARN ABOUT PHP
datetime.__construct
DATETIME.__CONSTRUCT(3) 1 DATETIME.__CONSTRUCT(3)DateTime::__construct - Returns new DateTime object
Object oriented style
SYNOPSIS
public DateTime::__construct NULL ([string $time = "now"], [DateTimeZone $timezone])
DESCRIPTION
Procedural style
DateTime date_create NULL ([string $time = "now"], [DateTimeZone $timezone])
Returns new DateTime object.
PARAMETERS
o $time
-A date/time string. Valid formats are explained in Date and Time Formats. Enter NULL here to obtain the current time when using
the $timezone parameter.
o $timezone
- A DateTimeZone object representing the timezone of $time. If $timezone is omitted, the current timezone will be used.
Note
The $timezone parameter and the current timezone are ignored when the $time parameter either is a UNIX timestamp (e.g.
@946684800) or specifies a timezone (e.g. 2010-01-28T15:00:00+02:00).
RETURN VALUES
Returns a new DateTime instance. Procedural style returns FALSE on failure.
ERRORS /EXCEPTIONS
Emits Exception in case of an error.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | If $time contains an invalid date/time format, |
| | then an exception is now thrown. Previously an |
| | error was emitted. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.__construct(3) example
Object oriented style
<?php
try {
$date = new DateTime('2000-01-01');
} catch (Exception $e) {
echo $e->getMessage();
exit(1);
}
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
if (!$date) {
$e = date_get_last_errors();
foreach ($e['errors'] as $error) {
echo "$error
";
}
exit(1);
}
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-01
Example #2
Intricacies of DateTime.__construct(3)
<?php
// Specified date/time in your computer's time zone.
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:sP') . "
";
// Specified date/time in the specified time zone.
$date = new DateTime('2000-01-01', new DateTimeZone('Pacific/Nauru'));
echo $date->format('Y-m-d H:i:sP') . "
";
// Current date/time in your computer's time zone.
$date = new DateTime();
echo $date->format('Y-m-d H:i:sP') . "
";
// Current date/time in the specified time zone.
$date = new DateTime(null, new DateTimeZone('Pacific/Nauru'));
echo $date->format('Y-m-d H:i:sP') . "
";
// Using a UNIX timestamp. Notice the result is in the UTC time zone.
$date = new DateTime('@946684800');
echo $date->format('Y-m-d H:i:sP') . "
";
// Non-existent values roll over.
$date = new DateTime('2000-02-30');
echo $date->format('Y-m-d H:i:sP') . "
";
?>
The above example will output something similar to:
2000-01-01 00:00:00-05:00
2000-01-01 00:00:00+12:00
2010-04-24 10:24:16-04:00
2010-04-25 02:24:16+12:00
2000-01-01 00:00:00+00:00
2000-03-01 00:00:00-05:00
SEE ALSO DateTime.createFromFormat(3), DateTimeZone.__construct(3), Date and Time Formats, date.timezone ini setting, date_default_time-
zone_set(3), DateTime.getLastErrors(3), checkdate(3).
PHP Documentation Group DATETIME.__CONSTRUCT(3)