03-13-2020
You'd probably better read into: man crontab for your timing issue.
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hello all,
I want to create a script that polls every hour a directory for the existence of a file. The file I look for is a `token` dropped by an external process at the completion of a successful FTP process. I wrote this script `checkfile.ksh`:
#!/usr/bin/ksh
if ] then
mailx... (5 Replies)
Discussion started by: alan
5 Replies
2. Shell Programming and Scripting
Hi,
i am getting following syntax error ...kingly advice why is it coming ??
#!/bin/bash
find . -name "common.log"
if ; then
echo "1"
fi
Himnashu@home /bin
$ ./a.sh
./a.sh: line 7: syntax error near unexpected token `fi'
./a.sh: line 7: `fi' (9 Replies)
Discussion started by: himvat
9 Replies
3. Shell Programming and Scripting
Hi all,
Am very new to Unix and am currently Involved in Migrating some Shell Scripts from AIX 4 to Solaris 10.
While using teh for loop am getting the below error:
$ echo $SHELL
/usr/bin/ksh
$ for file in $(ls *SEBE*)
syntax error: `$' unexpected
while the same works without issue on... (4 Replies)
Discussion started by: paragkhanore
4 Replies
4. Shell Programming and Scripting
So I am trying to convert my bash script into ksh, and this is what I have in the file so far:
#!/bin/ksh
login()
{
if
then
sendcmd BETA
else
sendcmd "$(xxd -c 32 -g 0 ${ZETA_ZETA} | awk '{print $2}')"
fi
}
But when I run it:
$ ./test.sh ... (1 Reply)
Discussion started by: guitarscn
1 Replies
5. Shell Programming and Scripting
Issue resolved, thanks (6 Replies)
Discussion started by: dangell82
6 Replies
6. Shell Programming and Scripting
unzip file.zip
if ] ; then
echo "Success"
else
echo "Some failure."
fi ;
I tried many time to detect the unzip error, but it keep show the syntax error wherever how I change the syntac. Hope someone can help me fix the issue, thanks.
Please use code tags next time for your code and... (5 Replies)
Discussion started by: duncanyy
5 Replies
7. Shell Programming and Scripting
I have written this in my script but while running i am getting syntax error `(' unexpected.
unload to "$BACKUP_DIR/n_fac_fid-$clliname" select * from n_fac_fid where fac_accesskey in (select fac_accesskey From n_fac_ap_fid where ap_clli="$clliname");
Any help appreciated. (3 Replies)
Discussion started by: suryanmi
3 Replies
8. UNIX for Beginners Questions & Answers
Dears,
While executing the below script im getting the error at line 30. Please let me know what changes to be done to fix this.
test.sh: line 30: syntax error near unexpected token `done'
test.sh: line 30: ` done '
#!/bin/sh
# Rev. PA1
# author: eillops
# date: 26-04-2018
#
#... (1 Reply)
Discussion started by: Kamesh G
1 Replies
9. Shell Programming and Scripting
I am getting this error Syntax error: `]' unexpected. Did I do something wrong with elif? Does ksh not like double brackets?
if ]; then
#echo hi
source ~/.bashrc;
elif ]; then
#echo hi
source ~/.kshrc;
fi (5 Replies)
Discussion started by: cokedude
5 Replies
10. Shell Programming and Scripting
I've been trying to figure this issue for almost 2 hours now...
I dont see/find any typos or other code mismatches.. but maybe i'm looking at the wrong places....
Here's the console output:
$ LC_ALL=C
$ cd prjs/SWARM/ ; time source ./rc
bash: cd: prjs/SWARM/: No such file or directory... (3 Replies)
Discussion started by: sea
3 Replies
ECHO(3) 1 ECHO(3)
echo - Output one or more strings
SYNOPSIS
void echo (string $arg1, [string $...])
DESCRIPTION
Outputs all parameters.
echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other
language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want
to pass more than one parameter to echo, the parameters must not be enclosed within parentheses.
echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn-
tax only works with the short_open_tag configuration setting enabled.
I have <?=$foo?> foo.
PARAMETERS
o $arg1
- The parameter to output.
o $...
-
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
echo examples
<?php
echo "Hello World";
echo "This spans
multiple lines. The newlines will be
output as well";
echo "This spans
multiple lines. The newlines will be
output as well.";
echo "Escaping characters is done "Like this".";
// You can use variables inside of an echo statement
$foo = "foobar";
$bar = "barbaz";
echo "foo is $foo"; // foo is foobar
// You can also use arrays
$baz = array("value" => "foo");
echo "this is {$baz['value']} !"; // this is foo !
// Using single quotes will print the variable name, not the value
echo 'foo is $foo'; // foo is $foo
// If you are not using any other characters, you can just echo variables
echo $foo; // foobar
echo $foo,$bar; // foobarbarbaz
// Some people prefer passing multiple parameters to echo over concatenation.
echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10);
echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . "
";
echo <<<END
This uses the "here document" syntax to output
multiple lines with $variable interpolation. Note
that the here document terminator must appear on a
line with just a semicolon. no extra whitespace!
END;
// Because echo does not behave like a function, the following code is invalid.
($some_var) ? echo 'true' : echo 'false';
// However, the following examples will work:
($some_var) ? print 'true' : print 'false'; // print is also a construct, but
// it behaves like a function, so
// it may be used in this context.
echo $some_var ? 'true': 'false'; // changing the statement around
?>
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
SEE ALSO
print(3), printf(3), flush(3), Heredoc syntax.
PHP Documentation Group ECHO(3)