03-13-2020
You'd probably better read into: man crontab for your timing issue.
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1. Shell Programming and Scripting
Hello all,
I want to create a script that polls every hour a directory for the existence of a file. The file I look for is a `token` dropped by an external process at the completion of a successful FTP process. I wrote this script `checkfile.ksh`:
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if ] then
mailx... (5 Replies)
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2. Shell Programming and Scripting
Hi,
i am getting following syntax error ...kingly advice why is it coming ??
#!/bin/bash
find . -name "common.log"
if ; then
echo "1"
fi
Himnashu@home /bin
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3. Shell Programming and Scripting
Hi all,
Am very new to Unix and am currently Involved in Migrating some Shell Scripts from AIX 4 to Solaris 10.
While using teh for loop am getting the below error:
$ echo $SHELL
/usr/bin/ksh
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syntax error: `$' unexpected
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4. Shell Programming and Scripting
So I am trying to convert my bash script into ksh, and this is what I have in the file so far:
#!/bin/ksh
login()
{
if
then
sendcmd BETA
else
sendcmd "$(xxd -c 32 -g 0 ${ZETA_ZETA} | awk '{print $2}')"
fi
}
But when I run it:
$ ./test.sh ... (1 Reply)
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5. Shell Programming and Scripting
Issue resolved, thanks (6 Replies)
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6. Shell Programming and Scripting
unzip file.zip
if ] ; then
echo "Success"
else
echo "Some failure."
fi ;
I tried many time to detect the unzip error, but it keep show the syntax error wherever how I change the syntac. Hope someone can help me fix the issue, thanks.
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7. Shell Programming and Scripting
I have written this in my script but while running i am getting syntax error `(' unexpected.
unload to "$BACKUP_DIR/n_fac_fid-$clliname" select * from n_fac_fid where fac_accesskey in (select fac_accesskey From n_fac_ap_fid where ap_clli="$clliname");
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8. UNIX for Beginners Questions & Answers
Dears,
While executing the below script im getting the error at line 30. Please let me know what changes to be done to fix this.
test.sh: line 30: syntax error near unexpected token `done'
test.sh: line 30: ` done '
#!/bin/sh
# Rev. PA1
# author: eillops
# date: 26-04-2018
#
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9. Shell Programming and Scripting
I am getting this error Syntax error: `]' unexpected. Did I do something wrong with elif? Does ksh not like double brackets?
if ]; then
#echo hi
source ~/.bashrc;
elif ]; then
#echo hi
source ~/.kshrc;
fi (5 Replies)
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10. Shell Programming and Scripting
I've been trying to figure this issue for almost 2 hours now...
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Here's the console output:
$ LC_ALL=C
$ cd prjs/SWARM/ ; time source ./rc
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LEARN ABOUT PHP
datetime.__construct
DATETIME.__CONSTRUCT(3) 1 DATETIME.__CONSTRUCT(3)
DateTime::__construct - Returns new DateTime object
Object oriented style
SYNOPSIS
public DateTime::__construct NULL ([string $time = "now"], [DateTimeZone $timezone])
DESCRIPTION
Procedural style
DateTime date_create NULL ([string $time = "now"], [DateTimeZone $timezone])
Returns new DateTime object.
PARAMETERS
o $time
-A date/time string. Valid formats are explained in Date and Time Formats. Enter NULL here to obtain the current time when using
the $timezone parameter.
o $timezone
- A DateTimeZone object representing the timezone of $time. If $timezone is omitted, the current timezone will be used.
Note
The $timezone parameter and the current timezone are ignored when the $time parameter either is a UNIX timestamp (e.g.
@946684800) or specifies a timezone (e.g. 2010-01-28T15:00:00+02:00).
RETURN VALUES
Returns a new DateTime instance. Procedural style returns FALSE on failure.
ERRORS
/EXCEPTIONS
Emits Exception in case of an error.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | If $time contains an invalid date/time format, |
| | then an exception is now thrown. Previously an |
| | error was emitted. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.__construct(3) example
Object oriented style
<?php
try {
$date = new DateTime('2000-01-01');
} catch (Exception $e) {
echo $e->getMessage();
exit(1);
}
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
if (!$date) {
$e = date_get_last_errors();
foreach ($e['errors'] as $error) {
echo "$error
";
}
exit(1);
}
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-01
Example #2
Intricacies of DateTime.__construct(3)
<?php
// Specified date/time in your computer's time zone.
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:sP') . "
";
// Specified date/time in the specified time zone.
$date = new DateTime('2000-01-01', new DateTimeZone('Pacific/Nauru'));
echo $date->format('Y-m-d H:i:sP') . "
";
// Current date/time in your computer's time zone.
$date = new DateTime();
echo $date->format('Y-m-d H:i:sP') . "
";
// Current date/time in the specified time zone.
$date = new DateTime(null, new DateTimeZone('Pacific/Nauru'));
echo $date->format('Y-m-d H:i:sP') . "
";
// Using a UNIX timestamp. Notice the result is in the UTC time zone.
$date = new DateTime('@946684800');
echo $date->format('Y-m-d H:i:sP') . "
";
// Non-existent values roll over.
$date = new DateTime('2000-02-30');
echo $date->format('Y-m-d H:i:sP') . "
";
?>
The above example will output something similar to:
2000-01-01 00:00:00-05:00
2000-01-01 00:00:00+12:00
2010-04-24 10:24:16-04:00
2010-04-25 02:24:16+12:00
2000-01-01 00:00:00+00:00
2000-03-01 00:00:00-05:00
SEE ALSO
DateTime.createFromFormat(3), DateTimeZone.__construct(3), Date and Time Formats, date.timezone ini setting, date_default_time-
zone_set(3), DateTime.getLastErrors(3), checkdate(3).
PHP Documentation Group DATETIME.__CONSTRUCT(3)