Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: Replace a field in a comma separated file
Top Forums UNIX for Beginners Questions & Answers Replace a field in a comma separated file Post 303044850 by H squared on Thursday 5th of March 2020 09:58:41 AM
Old 03-05-2020
Thanks for the quick response.

I would mention that the number of arguments calling the script could be more than 2 and the number of fields to be transformed can be more than 2.

The field # 12 (though not present in my sample file) would be a new date field that would be transformed.

Could you please share your thoughts on this.

Please let me know if you need more inputs from my end.

Quote:
Originally Posted by vgersh99
a bit verbose and can be simplified - just following your description.

Code:
 awk -v fld='5,8' -f hsquared.awk myFile.csv

where hsquared.awk is:
Code:
BEGIN {
  FS=OFS=","
  fld=(!fld)?"5":fld
  fldN=split(fld, fldA,FS)
}
function convF(str ) {
 return (substr(str,1,4) "-" substr(str,5,2) "-" substr(str,7))
}
{
   for(i=1;i<=fldN;i++) {
     if ($(fldA[i]-1)==0 && $(fldA[i])!=0)
       $(fldA[i])=convF("19" $(fldA[i]))

     if ($(fldA[i]-1)==0 && $(fldA[i])==0)
       $(fldA[i])=convF("00010101")

     if ($(fldA[i]-1)==1) {
        if (length($(fldA[i])) == 5)
           $(fldA[i])=convF("200" $(fldA[i]))
        else
           $(fldA[i])=convF("20" $(fldA[i]))
     }

   }
}
1

results in:
Code:
29,A Store,A Street,1,2011-12-13,aaaa,0,1989-12-13
30,B Store,B Street,0,1999-12-13,aaaa,1,2006-12-13
31,C Store,C Street,1,2005-12-13,aaaaa,1,2008-12-13
32,D Store,D Street,0,0001-01-01,aaaa,1,2015-03-23
33,E Store,E Street,1,2012-12-12,bbbb,0,0001-01-01
34,F Store,F Street,1,2010-12-12,cccc,0,1997-12-12

awk -f hsquared.awk myFile.csv will do only field 5 by default
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Its PERL + Comma separated seventh field

Hi Friends, I'm working on a perl script, which seems to be simpler. But I'm very new to PERL scripting. I have a comma separated data file, from which I need to extract only the seventh field data out of available twenty fields to an array using perl. Any help would be much appreciated. ... (17 Replies)
Discussion started by: ganapati
17 Replies

2. Shell Programming and Scripting

Replace comma by space for specified field in record

Hi, i want to replace comma by space for specified field in record, i mean i want to replace the commas in the 4th field by space. and rest all is same throught the record. the record is 16458,99,001,"RIMOUSKI, QC",418,"N",7,EST,EDT,902 16458,99,002,"CHANDLER,... (5 Replies)
Discussion started by: raghavendra.cse
5 Replies

3. Shell Programming and Scripting

How to format file into comma separated field

Guys, Need you help, i have a a file content that look like this. Nokia 3330 <spaces><spaces><more spaces>+76451883874 Nokia 3610 +87467361615 so on and so forth, - there are so many spaces in between. - e.g.... (5 Replies)
Discussion started by: shtobias
5 Replies

4. Shell Programming and Scripting

Inserting string in between field in comma separated file

Hello Mates, I have one txt file having commo seperated values. I have to insert string "FALSE" in 2nd field from the end. E.G SE18 6RN,,,,5439070,1786840,,1000002148671600,123434 Out put should be: SE18 6RN,,,,5439070,1786840,FALSE,1000002148671600,123434 Can some one help me to... (8 Replies)
Discussion started by: krsnadasa
8 Replies

5. Shell Programming and Scripting

Comma separated file

Hi all, I have the following files types: FileA: 100, 23, 33, FileB: 22, 45, 78, and i want to make File C: 100,22 23,45 33,78 any nice suggestions for making it easy. (3 Replies)
Discussion started by: hen1610
3 Replies

6. Shell Programming and Scripting

Need Help - comma inside double quote in comma separated csv,

Hello there, I have a comma separated csv , and all the text field is wrapped by double quote. Issue is some text field contain comma as well inside double quote. so it is difficult to process. Input in the csv file is , 1,234,"abc,12,gh","GH234TY",34 I need output like below,... (8 Replies)
Discussion started by: Uttam Maji
8 Replies

7. Shell Programming and Scripting

How to split the comma separated file?

Hi, I have a filein unix like ABC,CDE BCD,KHL and the output i need is like column1 column2 ABC,CDE ABC ABC,CDE CDE BCD,KHL BCD BCD,KHL KHL. Can some body help me out? Hi, The code is working fine. But in my file each row does not have always 1 comma. It may... (6 Replies)
Discussion started by: jagdishrout
6 Replies

8. UNIX for Dummies Questions & Answers

[solved] Comma separated values to space separated

Hi, I have a large number of files which are written as csv (comma-separated values). Does anyone know of simple sed/awk command do achieve this? Thanks! ---------- Post updated at 10:59 AM ---------- Previous update was at 10:54 AM ---------- Guess I asked this too soon. Found the... (0 Replies)
Discussion started by: lost.identity
0 Replies

9. Shell Programming and Scripting

Comma separated to rows based on field

Hi to all, I have a file like: chr1 a1 a2 a3 a4 a5 a6,a7,a8,a9 chr1 b1 b2 b3 b4 b5 b6,b7 chr2 c1 c2 c3 c4 c5 c6,c7,c8,c9,c10 ... I would like an output like this: chr1 a6 chr1 a7 chr1 a8 chr1 a9 chr1 b6 chr1 b7 chr2 c6 chr2 c7 chr2 c8 (6 Replies)
Discussion started by: aec
6 Replies

10. Shell Programming and Scripting

awk to parse comma separated field and removing comma in between number and double quotes

Hi Experts, Please support I have below data in file in comma seperated, but 4th column is containing comma in between numbers, bcz of which when i tried to parse the file the column 6th value(5049641141) is being removed from the file and value(222.82) in column 5 becoming value of column6. ... (3 Replies)
Discussion started by: as7951
3 Replies

LEARN ABOUT REDHAT

join

JOIN(1) 								FSF								   JOIN(1)

NAME

       join - join lines of two files on a common field

SYNOPSIS

       join [OPTION]... FILE1 FILE2

DESCRIPTION

       For  each  pair of input lines with identical join fields, write a line to standard output.  The default join field is the first, delimited
       by whitespace.  When FILE1 or FILE2 (not both) is -, read standard input.

       -a SIDE
	      print unpairable lines coming from file SIDE

       -e EMPTY
	      replace missing input fields with EMPTY

       -i, --ignore-case ignore differences in case when comparing fields

       -j FIELD
	      (obsolescent) equivalent to `-1 FIELD -2 FIELD'

       -j1 FIELD
	      (obsolescent) equivalent to `-1 FIELD'

       -j2 FIELD
	      (obsolescent) equivalent to `-2 FIELD'

       -o FORMAT
	      obey FORMAT while constructing output line

       -t CHAR
	      use CHAR as input and output field separator

       -v SIDE
	      like -a SIDE, but suppress joined output lines

       -1 FIELD
	      join on this FIELD of file 1

       -2 FIELD
	      join on this FIELD of file 2

       --help display this help and exit

       --version
	      output version information and exit

       Unless -t CHAR is given, leading blanks separate fields and are ignored, else fields are separated by CHAR.  Any FIELD is  a  field  number
       counted from 1.	FORMAT is one or more comma or blank separated specifications, each being `SIDE.FIELD' or `0'.	Default FORMAT outputs the
       join field, the remaining fields from FILE1, the remaining fields from FILE2, all separated by CHAR.

AUTHOR

       Written by Mike Haertel.

REPORTING BUGS

       Report bugs to <bug-coreutils@gnu.org>.

COPYRIGHT

       Copyright (C) 2002 Free Software Foundation, Inc.
       This is free software; see the source for copying conditions.  There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICU-
       LAR PURPOSE.

SEE ALSO

       The  full documentation for join is maintained as a Texinfo manual.  If the info and join programs are properly installed at your site, the
       command

	      info join

       should give you access to the complete manual.

join (coreutils) 4.5.3						   February 2003							   JOIN(1)
All times are GMT -4. The time now is 08:18 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy