03-02-2020
I tried to do using bedtools makewindows option and bedops chop option, but none of them worked as I need.
This is why I asked here. I know this forum or another forums are not a script writing service. This is the best I can do because my efforts that I know did not worked.
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Hi,
I am new to this forum and new to awk.
I have a file that contains 2 columns.
Heres an example of what it looks like:
10 +
20 +
40 +
50 -
70 -
So the file is tab-delimited. What I want to do is add 10 to column 1 whenever column 2 is + and substract 10 from column 1... (1 Reply)
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2. Shell Programming and Scripting
Dear All,
I would like to split a file of the following format into multiple files based on the number in the 6th column (numbers 1, 2, 3...):
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Hi,
I have a file sample_1.txt (300k rows) which has data like below:
* Also each record is around 64k bytes
11|1|abc|102553|125589|64k bytes of data
10|2|def|123452|123356|......
13|2|geh|144351|121123|...
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I have a following inputfile
MT,AP,CDM,TTML,MUM,GS,SUCC,3
MT,AP,CDM,TTSL,AP,GS,FAIL,9
MT,AP,CDM,RCom,MAH,GS,SUCC,3
MT,AP,CDM,RTL,HP,GS,SUCC,1
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Hi,
I have a similar input format-
A_1 2
B_0 4
A_1 1
B_2 5
A_4 1
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letter number_of_letters... (5 Replies)
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Hi,
I have a table to be imported for R as matrix or data.frame but I first need to edit it because I've got several lines with the same identifier (1st column), so I want to sum the each column (2nd -nth) of each identifier (1st column)
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please write a shell script
Table
--------------------------
1 2 3 a b c
3 4 5 c d e
7 8 9 f g h
Output should be like this
---------------
1 2 3
3 4 5
7 8 9
a b c
c d e
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Split column data if the table has n number of column's with some record then how to split n number of colmn's line by line with records
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---------
Col1 col2 col3 col4 ....................col20
1 2 3 4 .................... 20
a b c d .................... v
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Hello,
I am trying to store sum of a column as a new column inside a file but have to find the column names dynamically
I/p
c1,c2,c3,c4,c5
10,20,30,40,50
20,30,40,50,60
If i want to find sum only column c1, c3 and output it as c6,c7
O/p
c1,c2,c3,c4,c5,c6,c7
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Hi All,
I have a file as below and want to sum based on the id in the first column
Input
10264;ATE; 12
10265;SES;11
10266AUT;50
10264;ATE;10
10265;SES;13
10266AUT;89
10264;ATE;1
10265;SES;15
10266AUT;78
Output
10264;ATE; 23
10265;SES;39
10266AUT;139 (6 Replies)
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LEARN ABOUT CENTOS
crontabs
CRONTABS(4) Crontabs users' Manual CRONTABS(4)
NAME
crontabs - configuration and scripts for running periodical jobs
SYNOPSIS
run-parts [--list|--test]<directory>
DESCRIPTION
Crontabs is a historical name for the run-parts script and the system crontab. The run-parts script runs all executables in the specified
directory. Run-parts runs all executables in the specified directory. The execution of files can be allowed or denied by creating file
jobs.allow or jobs.deny which worked similar as other allow/deny config files. The file must be created in the specified directory.
--list print names of all files (not limited to executables), but don't run them. This option can't be used with test option.
--test print names of files, which would be run.
Randomization of jobs can be configured in the /etc/sysconfig/run-parts file. To enable randomization of jobs, set the RANDOMIZE
parameter to 1 and set the RANDOM parameter to an integer which determines a random seed. Additionally, you may configure the RAN-
DOMTIME parameter (again, by specifying an integer) to provide an additional level of randomization. Jobs are not randomized when
the RANDOM and RANDOMTIME parameters are set to 0. Values in these two parameters must be set to 1 or larger to provide a good
enough randomization.
Randomization of cron jobs can be useful for shared networks, where multiple cron jobs executed at once can cause spikes in traffic,
especially during daily jobs. With randomized jobs, the workload is evenly distributed throughout the day.
EXAMPLE OF CONFIGURATION FILE
RANDOMIZE=1
RANDOM=4
RANDOMTIME=8
Historically the crontab file contained configuration which called run-parts on files in cron.{daily,weekly,monthly} directories. These
jobs are now run indirectly through anacron to prevent conflicts between cron and anacron. That means the anacron package has to be
installed if the jobs in these directories should be running. Refer to the anacron(8) how to limit the time of day of the job execution.
EXAMPLE
/etc/cron.daily/jobs.deny could contain for example 0logwatch which forbid execution of this script.
SEE ALSO
anacron(8), crontab(5)
Marcela Malaova 2012-08-29 CRONTABS(4)