02-15-2020
Quote:
To all
Please pay attention to what is displayed at the top of this discussion: We are awaiting a reply from the O/P any solution posted till then will be hidden
Thanks for your understanding
Thank you vbe,
Yes, this is the correct approach, especially when additional information is requested by a Moderator, in this case, vgersh99 .
It is important that posters, especially these "fly into the site, register, and post" users follow community guidelines and Moderator instructions.
Thank you very much vbe and vgersh99 for your dedication to helping the community and your well-developed moderation skills.
If the OP does not reply back in few days (your judgement call on how many days), then we can "unhide" the two solutions presented so far.
Thanks for the solutions and replies as well!
Good work everyone.
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Hi Friends,
Scripting newb here. So I'm trying to create a geektool script that uses awk and printf to output certain fields from top (namely command, cpu%, rsize, pid and time, in that order).
Here's the input from the top process that I'm putting into awk:
PID COMMAND %CPU ... (3 Replies)
Discussion started by: thom.mattson
3 Replies
2. Shell Programming and Scripting
Hi All,
I was wondering if anyone knew how to dynamically change the FS in awk to accept vairiable containing a field separator. the current code is as below and does not work when i introduce the dynamic FS change :-(
validate_source_file()
{
source_file=$1
... (2 Replies)
Discussion started by: satnamx
2 Replies
3. Shell Programming and Scripting
Hi
I need to check if field separator I am using in awk statement is " : ", for example:
TIME=12:59
HOUR=`echo "$TIME" | awk '{FS=":"; print $1}'`
MINUTES=`echo "$TIME" | awk '{FS=":"; print $2}'`
Is there a way to check within the above awk statement ?
Thanks for help -A (2 Replies)
Discussion started by: aoussenko
2 Replies
4. Shell Programming and Scripting
Hi;
i have a file and i want to get;
- If the last word in line 14 is NOT equal to "Set."; then print 2nd, 3rd, 4th and 5th values of 3rd line.
and my code is:
nawk 'NR==14 {if ($NF!="Set.") (NR==3{print $2,$3,$4,$5}) }' file.txt
but no result?? :confused::(:confused::( (4 Replies)
Discussion started by: gc_sw
4 Replies
5. Shell Programming and Scripting
Hi, all
I need to get fields in a line that are separated by commas, some of the fields are enclosed with double quotes, and they are supposed to be treated as a single field even if there are commas inside the quotes.
sample input:
for this line, 5 fields are supposed to be extracted, they... (8 Replies)
Discussion started by: kevintse
8 Replies
6. Shell Programming and Scripting
I am using this code to insert something into a csv file:
awk -F";" -v url=$url -v nr=$nr 'NR==nr{$2=url$2}1' file
Why do I get the output
field1 field2
instead of
field1;field2
I have given -F";", so the field separator should surely be ";". (1 Reply)
Discussion started by: locoroco
1 Replies
7. UNIX for Dummies Questions & Answers
In awk, how do I print all fields with a specified output field separator?
I have tried the following, which does not print the output FS:
echo a b c d | awk 'BEGIN{OFS = ";"}{print $0}' (3 Replies)
Discussion started by: locoroco
3 Replies
8. Shell Programming and Scripting
I need to set awk field separator to ";", but I need to avoid ";EXT".
so that
echo a;b;c;EXTd;e;f | awk -F";" '{print $3}'
would give "c;EXTd" (2 Replies)
Discussion started by: locoroco
2 Replies
9. Shell Programming and Scripting
Hi Experts ,
file :
- How to construct the awk filed separator so that $1, $2 $3 , can be assigned to the each "" range.
I am trying : awk -F"]" '{print $1}'
but it is printing the entire file. Not first field.
The desired output needed for first field... (9 Replies)
Discussion started by: rveri
9 Replies
10. Shell Programming and Scripting
I can not figure out how to set the Output filed separator in awk when using printf.
Example:
cat file
some data
here_is_more information
Requested output
some------------data
her_is_more-----information
Here are some that does not work:
awk '{printf "%-15s %s\n",$1,$2}' OFS="-" file... (9 Replies)
Discussion started by: Jotne
9 Replies
LEARN ABOUT DEBIAN
dpkg-ruby
DPKG-RUBY(1) General Commands Manual DPKG-RUBY(1)
NAME
dpkg-ruby - Utility to read a dpkg style db file, dpkg-awk clone
SYNOPSIS
dpkg-ruby [(-f|--file) filename] [(-d|--debug) ##] [(-s|--sort) list] [(-n|--numeric) list] [(-rs|--rec_sep) ??] '<fieldname>:<regex>' ...
-- <out_fieldname> ..
DESCRIPTION
dpkg-ruby Parses a dpkg status file(or other similarly formated file) and outputs the resulting records. It can use regex on the field
values to limit the returned records, and it can also be told which fields to output. As another option, it can sort the matched fields.
OPTIONS
-f filename
--file filename
The file to parse. The default is /var/lib/dpkg/status.
-d [#]
--debug [#]
Each time this is specified, it increased the debug level.
-s field(s)
--sort field(s)
A space or comma separated list of fields to sort on.
-n field(s)
--numeric field(s)
A space or comma separated list of fields that should be interpreted as numeric in value.
-rs ??
--rec_sep ??
Output this string at the end of each output paragraph.
-h
--help Display some help.
fieldname
The fields from the file, that are matched with the regex given. The fieldnames are case insensitive.
out_fieldname
The fields from the file, that are outputted for each record. If the first field listed is begins with ^, then the list that fol-
lows are fields NOT to be outputted.
BUGS
Be warned that the author has only a shallow understanding of the dpkg packaging system, so there are probably tons of bugs in this pro-
gram.
This program comes with no warranties. If running this program causes fire and brimstone to rain down upon the earth, you will be on our
own.
This program accesses the dpkg database directly in places, querying for data that cannot be gotten via dpkg.
AUTHOR
Fumitoshi UKAI <ukai@debian.or.jp>. This manual page are based on (or almost copy from :) dpkg-awk(1) manual written by Adam Heath <doo-
gie@debian.org>
DEBIAN
Debian Utilities DPKG-RUBY(1)