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Top Forums Shell Programming and Scripting How do we display specific row of an output from bottom given line number? Post 303043986 by mohtashims on Wednesday 12th of February 2020 06:33:45 AM
Old 02-12-2020
How do we display specific row of an output from bottom given line number?

I pass a number to my script. Passing "1" below.

Code:
./getfile.sh 1
echo "User entered: $1"
 ls -ltr *.conf | sed -n '$p'

I wish to use ls -ltr i.e list files in ascending order of time the latest showing at the bottom of the output.

Number 1 should get me the last row of ls -ltr output i.e the latest file.
Passing Number "2" should get me the second last row of the output.
Number "3 would get me the 3rd last row and so forth.

I wish to use only sed for this purpose as it is works smoothy across different flavors of Operating Systems that I have.

ls -ltr | sed -n '$p' gives me the last row whereas ls -ltr | sed -n 3p gives me the third row from top.

I'm not sure how can I give an equation so that based on user input, I could get my sed to display corresponding row of output.
 

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SQLSRV_FETCH(3) 														   SQLSRV_FETCH(3)

sqlsrv_fetch - Makes the next row in a result set available for reading

SYNOPSIS
mixed sqlsrv_fetch (resource $stmt, [int $row], [int $offset]) DESCRIPTION
Makes the next row in a result set available for reading. Use sqlsrv_get_field(3) to read the fields of the row. PARAMETERS
o $stmt - A statement resource created by executing sqlsrv_query(3) or sqlsrv_execute(3). o $row - The row to be accessed. This parameter can only be used if the specified statement was prepared with a scrollable cursor. In that case, this parameter can take on one of the following values: oSQLSRV_SCROLL_NEXT oSQLSRV_SCROLL_PRIOR oSQLSRV_SCROLL_FIRST oSQLSRV_SCROLL_LAST oSQLSRV_SCROLL_ABSOLUTE oSQLSRV_SCROLL_RELATIVE o $offset - Specifies the row to be accessed if the row parameter is set to SQLSRV_SCROLL_ABSOLUTE or SQLSRV_SCROLL_RELATIVE. Note that the first row in a result set has index 0. RETURN VALUES
Returns TRUE if the next row of a result set was successfully retrieved, FALSE if an error occurs, and NULL if there are no more rows in the result set. EXAMPLES
Example #1 sqlsrv_fetch(3) example The following example demonstrates how to retrieve a row with sqlsrv_fetch(3) and get the row fields with sqlsrv_get_field(3). <?php $serverName = "serverNamesqlexpress"; $connectionInfo = array( "Database"=>"dbName", "UID"=>"username", "PWD"=>"password"); $conn = sqlsrv_connect( $serverName, $connectionInfo); if( $conn === false ) { die( print_r( sqlsrv_errors(), true)); } $sql = "SELECT Name, Comment FROM Table_1 WHERE ReviewID=1"; $stmt = sqlsrv_query( $conn, $sql); if( $stmt === false ) { die( print_r( sqlsrv_errors(), true)); } // Make the first (and in this case, only) row of the result set available for reading. if( sqlsrv_fetch( $stmt ) === false) { die( print_r( sqlsrv_errors(), true)); } // Get the row fields. Field indeces start at 0 and must be retrieved in order. // Retrieving row fields by name is not supported by sqlsrv_get_field. $name = sqlsrv_get_field( $stmt, 0); echo "$name: "; $comment = sqlsrv_get_field( $stmt, 1); echo $comment; ?> SEE ALSO
sqlsrv_get_field(3), sqlsrv_fetch_array(3), sqlsrv_fetch_object(3). PHP Documentation Group SQLSRV_FETCH(3)
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