sorry for not mentioning. I'm using bash.
also apologies for the errors in the code. without space and adding $ in the cat also not helping much.
You seem to have missed the "expansion" of the variable in the echo statement?. Can you help me on this. I even tried printf but same result, or is there any other way I can get this output printed in a file.
Moderator's Comments:
Please use code tags when posting data and code samples!
Hi,
Working on AIX using the following for loop.
for a in `find /edi/iTracTEST/sessions -name nohup.out -print`
do
echo $a
done
On the command line it works fine, but insert the code in a file and then running it, it does not want to work. I get the following back.
' is not... (3 Replies)
hi friends,
i wrote one simple shell script.. in that am using for loop... when i am trying to execute the script.it shows syntax error at for loop line '((' unexpected.
#!/bin/ksh
##
##### To find no of files in the directory
NOF=`ls -l /root/COMM/LOGS/eds/20081025| wc -l`... (5 Replies)
Hi,
I get the following output
98 -1
98 0
./get_AB04-time: line 79: ((: i< && 0 !=7 : syntax error: operand expected (error token is "&& 0 !=7 ")
I have this part of code. Line 79 is the line of the for loop.
echo ${OCCURRENCE} $i_START
CASE=0;
i_END=${i_START}... (4 Replies)
Hello All,
I am having a problem with an “if loop” within a “while loop” in my Korn Shell program. The basic concept of the program is that it searches for the existence of a series of load files in a load directory, and once it finds one of these files, it begins the following process:
· Creates... (4 Replies)
the program just prints all the command line arguments
Getting error in the program
error
./hellow: line 13: 0: command not found
./hellow: line 13: 0: command not found
below is the program
#!/bin/bash
num=$#
echo $num
if
then
echo "No arguments are passed ."
else
... (7 Replies)
I have a file Table.out having table name like this
Table_Emp
Table_Exp
Table_Fcr
To show first 10 rows .. I' wrtng a script like this ..
#!/bin/ksh
cat /tmp/table.out|while read -r table vbar1
do
<connect to db>
then
select * from $table limit 10; > /tmp/1.out
done
... (3 Replies)
Hi All,
while executing this code ,I'm gettign below Error
if_test: line 3:
#!/bin/bash
if ;
then
echo "this is aginity;"
elif ;
then
echo "this is informatica;"
fi
exit (3 Replies)
This is my first ever bash script. What i wish to achieve is to find all files in current directory except the script file and count lines in each found file. Some thing seems to be wrong with the if statement :confused: Please help why it does not work? and maybe you have some ideas how to improve... (3 Replies)
I was trying to implement a nested for do loop to run a perl script.
for i in 1 10 50
do
for j in 2 12 55
do
perl script.pl "$i" "$i" "$j"
done
done
when I implemented it within a shell script, i got the output, but every time j value will 55, or basically the last value of j in... (10 Replies)
There are two files abc_123.dat and abc_345.dat if at least one file exists then enter into the loop and remove file and exit.
In first iteration, deleting files successfully
but "else" statement executing after deleting files."else" should execute only if there is no file in the directory.... (1 Reply)
Discussion started by: Rajesh123
1 Replies
LEARN ABOUT SUSE
unbuffer
UNBUFFER(1) General Commands Manual UNBUFFER(1)NAME
unbuffer - unbuffer output
SYNOPSIS
unbuffer program [ args ]
INTRODUCTION
unbuffer disables the output buffering that occurs when program output is redirected from non-interactive programs. For example, suppose
you are watching the output from a fifo by running it through od and then more.
od -c /tmp/fifo | more
You will not see anything until a full page of output has been produced.
You can disable this automatic buffering as follows:
unbuffer od -c /tmp/fifo | more
Normally, unbuffer does not read from stdin. This simplifies use of unbuffer in some situations. To use unbuffer in a pipeline, use the
-p flag. Example:
process1 | unbuffer -p process2 | process3
CAVEATS
unbuffer -p may appear to work incorrectly if a process feeding input to unbuffer exits. Consider:
process1 | unbuffer -p process2 | process3
If process1 exits, process2 may not yet have finished. It is impossible for unbuffer to know long to wait for process2 and process2 may
not ever finish, for example, if it is a filter. For expediency, unbuffer simply exits when it encounters an EOF from either its input or
process2.
In order to have a version of unbuffer that worked in all situations, an oracle would be necessary. If you want an application-specific
solution, workarounds or hand-coded Expect may be more suitable. For example, the following example shows how to allow grep to finish pro-
cessing when the cat before it finishes first. Using cat to feed grep would never require unbuffer in real life. It is merely a place-
holder for some imaginary process that may or may not finish. Similarly, the final cat at the end of the pipeline is also a placeholder
for another process.
$ cat /tmp/abcdef.log | grep abc | cat
abcdef
xxxabc defxxx
$ cat /tmp/abcdef.log | unbuffer grep abc | cat
$ (cat /tmp/abcdef.log ; sleep 1) | unbuffer grep abc | cat
abcdef
xxxabc defxxx
$
BUGS
The man page is longer than the program.
SEE ALSO
"Exploring Expect: A Tcl-Based Toolkit for Automating Interactive Programs" by Don Libes, O'Reilly and Associates, January 1995.
AUTHOR
Don Libes, National Institute of Standards and Technology
1 June 1994 UNBUFFER(1)