Use a here string
Use a here document
Use a code block (the variables can be used inside the code block)
Use the if statement as block and test if the variables are being read (the variables can be used inside the if statement).
This User Gave Thanks to Scrutinizer For This Post:
Hi :)
The next script campares two files File1-Line1 vs File2-Line1, File1-Line1 vs File2-Line2... only if line contains "AS-", if LineX is not in File2 writes in aux, but "valor" is allways=1 never changes! :confused: What is wrong?
valor changes to 0 before break, after brake is again 1
... (3 Replies)
How...
can I read input by a user character by cahracter. And assign each character from the string to a variable?
Any help would be greatly appreciated!
Thank you! (1 Reply)
Hi
I am trying to write a function that needs to be able to assign the last run shell command to a variable. The actual command string itself not the exit code of the command.
I am using the bash command recall ability to do this as follows:
alias pb='ps | grep ash' ... (3 Replies)
i have a file in this format
curyymm PRVYYMM CDDMmmYY bddMmmyy eddMmmyy
--------- ------- ------------ ---------- -----------
0906 0905 09Jun09 01Jun09 30Jun09
----------- --------- ------------ ------------ -----------
i need to read the... (5 Replies)
I have a csv file with the values seperated by commas.I want to extract these values one by one and assign to a variable using shell script.Any ideas or code? (11 Replies)
Hi all,
I want write a csh script which must be able:
1.read a file
2.assign value in file as variable
and can i use read in csh script?
thx (2 Replies)
Hi ,I am trying to assign string to variable ,but it doesn't work
Also could you show me different ways to use grep,(I am trying to get the first,second and first column form file,and I am counting the chars)
let name=`grep "$id" product | cut -c6-20` (25 Replies)
Hi,
I have a text file with multiple lines, each having data in the below format <DOB>,<ADDRESS>
I have to write a script which reads each line in the text file in loop, assign the values to these variables and do some further processing in it.
Using the following code prints the values... (12 Replies)
Hello,
I am using below code for reading from a file and assigning the values to a variable , but it is loosing the value after the loop , please suggest to retain the value of the variable after the loop ,
while IFS=: read -r line
do
set $dsc=$line
echo 'printing line variable ' $line... (1 Reply)
Discussion started by: ParthThakkar
1 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)