Hi,
I want to know how to change this string to date format
20061102122042 to 02-11-2006 12:20:42
or 02-Nov-2006 12:20:42
Please let me know at the earliest.Thanks in advance.
Regards,
Preetham R. (3 Replies)
I have a comma delimited log file which has the date as MM/DD/YY in the 2nd column, and HH:MM:SS in the 3rd column.
I need to change the date format to YYYY-MM-DD and merge it with the the time HH:MM:SS. How will I got about this?
Sample input
02/27/09,23:52:31
02/27/09,23:52:52... (3 Replies)
Hello!
I have a textfile that look like this:
"83d1:46:2b";"20091008190000";"Rögle BK - Skellefteå";"Swedish"
"d4c:46:21";"20091008190000";"Södertälje - Brynäs";"Swedish"
"d4b:46:2";"20091008190000";"HV 71 - Färjestad";"Swedish"
"838:46:b";"20091010160000";"Skellefteå - HV 71";"Swedish"... (2 Replies)
Dear Friends,
Need your help once again,
I have a variable ( e.g. ${i}) whoch has date in MM/DD/YYYY (E.g. 12/31/2011) format.
I want to change it to DD/MM/YYYY (e.g. 31/12/2011) format.
Request you to guide me as we are unable to do the same.
Thanks in advance
Anu. (1 Reply)
Hi,
i have a flat file namely temp.txt with this data below
ID|name|contact_date
101|Kay|2013-12-26
102|let|2013-12-26
I need to modify the date data in the flat file into MM/DD/YYYY HH24:MI:SS format
let me know the code for this.
Thank you! (5 Replies)
Hi,
I need help to convert the date format in .DAT file in unix.
I want to convert
10@@|SWIFT MT568 Extract@@|Apr 14 2014 5:47:52:563PM@@|Apr 14 2014 4:33:47:663PM@@||##|
into
10@@|SWIFT MT568 Extract@@|04/14/2014/ 5:47:52:563PM@@|04/14/2014 4:33:47:663PM@@||##|
Appreciate... (18 Replies)
Hi,
We have csv file where date is coming in MM/DD/YYYY HH:MM:SS (06/23/2015 20:59:12) in multiple places
But we need to change the date format to DD/Mon/YYYY HH:MM:SS (23/Jul/2015 20:59:12) using shell script.
Please let us know how can we achieve the same. (16 Replies)
Discussion started by: dholea
16 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)