i was attempting to extract a directory path that was passed from a parameter with this code
it does not work when the parameter passed has wild card on it.
for example
it works when not using a wild card (expanded file)
please help thank you.
Im trying to extract a directory from a path entered by the user
Lets say the path is
path=/home/bliss/files/myfile.txt
i wanna extract "/home/bliss/files" from $path ... how can i do this? (4 Replies)
Hi,
I have a environmental variables,
ORACLE_HOME=/u01/oracle/ORCL/db/tech/10.2.0
ORACLE_SID=ORCL
Now I need to create a variable and need to extract some part from ORACLE_HOME. I need to get the path from ORACLE_HOME till ORACLE_SID as /u01/oracle/ORCL. I may need to check also... (6 Replies)
Hi,
Could anyone help me in writing a single line code by either using (sed, awk, perl or whatever) to extract a specific path from the PATH environment variable?
for eg: suppose the PATH is being set as follows
PATH=/usr/bin/:/usr/local/bin:/bin:/usr/sbin:/usr/bin/java:/usr/bin/perl3.4
... (2 Replies)
Hi,
I have a function getparam() which takes parameter name as input and parameter value as output.
I have a strting like this,
abcd#paramname1#efgh#paramname2#ijklmnopq
Above one is my input,
The strting enclosed in # are the parameter names.
Here question is, I have to get the... (0 Replies)
Hi,
I have a file abcd.txt which has contents in the form of full path file names i.e.
$home> vi abcd.txt
/a/b/c/r1.txt
/q/w/e/r2.txt
/z/x/c/r3.txt
Now I want to retrieve only the directory path name for each row
i.e
/a/b/c/
/q/w/e/
How to get the same through shell script?... (7 Replies)
My input is as below :
/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt
/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt
/splunk/scrubbed/loyal/IFIND.HELLO.WROC.txt
/splunk/scrubbed/triumph/ifind.triumph.txt
From the above input I want to extract the file names only .
Basically I want to... (5 Replies)
Hello,
I am creating a file with all the source folders included in my git branch, when i grep for the used source, i found source included as relative path instead of absolute path, how can convert relative path to absolute path without changing directory to that folder and using readlink -f ? ... (4 Replies)
What is the difference ../directory path and ./directory path in ksh? (1 Reply)
Discussion started by: TestKing
1 Replies
LEARN ABOUT MOJAVE
cpanplus::internals::extract5.18
CPANPLUS::Internals::Extract(3pm) Perl Programmers Reference Guide CPANPLUS::Internals::Extract(3pm)NAME
CPANPLUS::Internals::Extract - internals for archive extraction
SYNOPSIS
### for source files ###
$self->_gunzip( file => 'foo.gz', output => 'blah.txt' );
### for modules/packages ###
$dir = $self->_extract( module => $modobj,
extractdir => '/some/where' );
DESCRIPTION
CPANPLUS::Internals::Extract extracts compressed files for CPANPLUS. It can do this by either a pure perl solution (preferred) with the
use of "Archive::Tar" and "Compress::Zlib", or with binaries, like "gzip" and "tar".
The flow looks like this:
$cb->_extract
Delegate to Archive::Extract
METHODS
$dir = _extract( module => $modobj, [perl => '/path/to/perl', extractdir => '/path/to/extract/to', prefer_bin => BOOL, verbose => BOOL, force
=> BOOL] )
"_extract" will take a module object and extract it to "extractdir" if provided, or the default location which is obtained from your
config.
The file name is obtained by looking at "$modobj->status->fetch" and will be parsed to see if it's a tar or zip archive.
If it's a zip archive, "__unzip" will be called, otherwise "__untar" will be called. In the unlikely event the file is of neither format,
an error will be thrown.
"_extract" takes the following options:
module
A "CPANPLUS::Module" object. This is required.
extractdir
The directory to extract the archive to. By default this looks something like:
/CPANPLUS_BASE/PERL_VERSION/BUILD/MODULE_NAME
prefer_bin
A flag indicating whether you prefer a pure perl solution, ie "Archive::Tar" or "Archive::Zip" respectively, or a binary solution like
"unzip" and "tar".
perl
The path to the perl executable to use for any perl calls. Also used to determine the build version directory for extraction.
verbose
Specifies whether to be verbose or not. Defaults to your corresponding config entry.
force
Specifies whether to force the extraction or not. Defaults to your corresponding config entry.
All other options are passed on verbatim to "__unzip" or "__untar".
Returns the directory the file was extracted to on success and false on failure.
perl v5.18.2 2014-01-06 CPANPLUS::Internals::Extract(3pm)