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Top Forums Programming Makefile missing include path Although the path exists and defined Post 303042726 by GRMartin on Saturday 4th of January 2020 01:13:13 PM
Old 01-04-2020
Quote:
Originally Posted by umen
i have make file which i try to make them generic
but it keeps to compline it missing include directory
this is the makefile :

Code:
 
when i invoke make , im getting this error:

     make
    g++    -c -o echo.o echo.cpp
    In file included from src/Server.h:9:0,
                     from echo.cpp:1:
    src/Client.h:6:10: fatal error: uv.h: No such file or directory
     #include <uv.h>
              ^~~~~~
    compilation terminated.
     make: *** [echo.o] Error 1

but the uv do exist in : /home/vagrant/libuv/include

You have several replies and I don't kow if your problem is solved but I'll mention that includes in <> are supposed to be for files in system directories i.e. /usr/include

Files in other directories should be referenced
Code:
#include "uv.h"

It's not been my experience that this causes compilation failures though.


-Greg.
This User Gave Thanks to GRMartin For This Post:
 

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EVAL(3) 								 1								   EVAL(3)

eval - Evaluate a string as PHP code

SYNOPSIS
mixed eval (string $code) DESCRIPTION
Evaluates the given $code as PHP. Caution The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged. If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user provided data into it without properly validating it beforehand. PARAMETERS
o $code - Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g. 'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error, whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe- cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible after it terminates. RETURN VALUES
eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to catch a parse error in eval(3) using set_error_handler(3). EXAMPLES
Example #1 eval(3) example - simple text merge <?php $string = 'cup'; $name = 'coffee'; $str = 'This is a $string with my $name in it.'; echo $str. " "; eval("$str = "$str";"); echo $str. " "; ?> The above example will output: This is a $string with my $name in it. This is a cup with my coffee in it. NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. Tip As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of this function, and save it in a string (for example). Note In case of a fatal error in the evaluated code, the whole script exits. SEE ALSO
call_user_func(3). PHP Documentation Group EVAL(3)
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