But if i want to include variables or pass arguments to regular expression then its giving me error "ls: cannot access /home/work/batch/somefilename_{27..96}.*: No such file or directory". But thats not true bec file is present but somehow with variables regex is not working.
Code:
>segStart="27"
>segEnd="96"
>myvar="$segStart..$segEnd"
>echo $segStart
27
>echo $segEnd
96
>echo $myvar
27..96
ls -d $WORKDIR/batch/somefilename_{$myvar}.*
"ls: cannot access /home/work/batch/somefilename_{27..96}.*: No such file or directory"
>array=($(ls -d $WORKDIR/batch/somefilename_$myvar.* 2>/dev/null))
>len=${#array[*]}
>echo $len
0
Can someone please advise here why the regular expression is not working when using ls and {..} with variables?
Note: I am trying to store all the directory names in an array whose directory name is between two integer number
for eg there are 1-100 dir available with name file_1.some file_2.some file_3.some .. file_100.some.
If user wants to get directory from 47 till 97, then i want to read that value, store them and pass it in above ls command.
If you have any other alternative that will also help.
Hi,
Actually i have written one test.sh (shell program) in bash.
Here i have a variables $a which stored the value package1.
Now I want to write a regular expression inside the if command that "if $a variable contains letter p in the begining of the value package1 then it is coming true.... (5 Replies)
Hi,
I have to match a certain pattern of string in my shell script:
6.0.4.11.9
7.5.1.7.1
First Number can be 6 or 7
Second number can be 0 or 5
Rest all numbers can be between 1-99
I am using following egrep:
egrep ^\.\.\.\.\$ filename
But why is the above regular... (1 Reply)
I have the following code:
ls -al /bin | tr -s ' ' | grep 'x'
ls -al: Lists all the files in a given director such as /bin
tr -s ' ': removes additional spaces between characters so that there is only one space
grep 'x': match all "x" characters that are followed by a whitespace.
I was... (3 Replies)
hi,
I have written a script to search MAC address in a given directory.
MAC address would be in format XX.XX.XX.XX.
The digits contain hexadecimal numbers.
For this i have used grep as follows.
grep -rn '^\{1,2\}\.\{1,2\}\.\{1,2\}\.\{1,2\}\$' *
This is not working as required.... (17 Replies)
Hi All,
I am facing some problems with regular expression with sed.
I have a .txt file with the contents as below:
This is a dummy file
# File created to test execution of regular expression.
Hope it works out.
As in the above contents there is a blank line which does not... (4 Replies)
Hi all,
How am I read a file, find the match regular expression and overwrite to the same files.
open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat";
open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat";
while (<DESTINATION_FILE>)
{
# print... (1 Reply)
Hello ,
Could anyone help me to define the string in regular expression way .
Below is my string
\rtf1\ansi\deff0{\fonttbl{\f0\fswiss Helv;}{\f1\fnil MS Sans Serif;}}
{\colortbl ;\red0\green0\blue0;}
\viewkind4\uc1\pard\cf1\lang1033\f0\fs16
The string will always start as \rtf1 and... (6 Replies)
How can I define a regular expression of a string which can start with Capital alphabet or integer (A-Z) or (0-9) and can be of any number of characters
I have tried * but its not working
could anyone please suggest? (2 Replies)
Hello Everyone,
I have a file sam1 with the below content
SYSYSID;MANDT;/SIE/AD_Z0M_INDX;/SIE/AD_Z0M_KEY1
echo $Regex
\bSYSYSID\b|\bMANDT\b|\b/SIE/AD_Z0M_INDX\b|\b/SIE/AD_Z0M_KEY1\b
cat sam1 | grep -Eo $Regex
I expect the result as
SYSYSID
MANDT
/SIE/AD_Z0M_INDX
/SIE/AD_Z0M_KEY1... (4 Replies)
Discussion started by: sam99
4 Replies
LEARN ABOUT ULTRIX
re_exec
regex(3) Library Functions Manual regex(3)Name
re_comp, re_exec - regular expression handler
Syntax
char *re_comp(s)
char *s;
re_exec(s)
char *s;
Description
The subroutine compiles a string into an internal form suitable for pattern matching. The subroutine checks the argument string against
the last string passed to
The subroutine returns 0 if the string s was compiled successfully; otherwise a string containing an error message is returned. If is
passed 0 or a null string, it returns without changing the currently compiled regular expression.
The subroutine returns 1 if the string s matches the last compiled regular expression, 0 if the string s failed to match the last compiled
regular expression, and -1 if the compiled regular expression was invalid (indicating an internal error).
The strings passed to both and may have trailing or embedded newline characters; they are terminated by nulls. The regular expressions
recognized are described in the manual entry for given the above difference.
Diagnostics
The subroutine returns -1 for an internal error.
The subroutine returns one of the following strings if an error occurs:
No previous regular expression
Regular expression too long
unmatched (
missing ]
too many () pairs
unmatched )
See Alsoed(1), ex(1), egrep(1), fgrep(1), grep(1)regex(3)
12-13-2019
