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Top Forums UNIX for Beginners Questions & Answers Echo For ... Loop output into a file Post 303041881 by RudiC on Thursday 5th of December 2019 04:53:15 PM
Old 12-05-2019
Please become accustomed to supplying decent and sufficient information. "But it didn't work." is not a good starting point for an analysis beyond guessing. Is That file created at all? Is it empty? Does it contain insufficient or even wrong data?


I'd expect two files to be created: one (empty!) in the starting directory, and one in /mydirectory, where you end up when the script is finished.
 

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starting(7)						 Miscellaneous Information Manual					       starting(7)

NAME
starting - event signalling that a job is starting SYNOPSIS
starting JOB=JOB INSTANCE=INSTANCE [ENV]... DESCRIPTION
The starting event is generated by the Upstart init(8) daemon when a new instance of a job begins starting. The JOB environment variable contains the job name, and the INSTANCE environment variable contains the instance name which will be empty for single-instance jobs. init(8) will wait for all services started by this event to be running, all tasks started by this event to have finished and all jobs stopped by this event to be stopped before allowing the job to continue starting. This allows jobs to effectively insert themselves as dependencies of other jobs. The event is typically combined with the stopped(7) event by services. Job configuration files may use the export stanza to export environment variables from their own environment into the starting event. See init(5) for more details. EXAMPLE
A service that wishes to be running whenever another service would be running, started before and stopped after it, might use: start on starting apache stop on stopped apache A task that must be run before another task or service is started might use: start on starting postgresql SEE ALSO
started(7) stopping(7) stopped(7) init(5) Upstart 2009-07-09 starting(7)
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