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Full Discussion: Unable to grep using wildcard in a file.
Top Forums Shell Programming and Scripting Unable to grep using wildcard in a file. Post 303041850 by mohtashims on Thursday 5th of December 2019 08:14:35 AM
Old 12-05-2019
Unable to grep using wildcard in a file.
I wish to check if my file has a line that does not start with '#' and has
1. Listen and 2. 443

Code:
 echo "Listen               443" > test.out

grep 'Listen *443' test.out | grep -v '#'
Listen               443

The above worked fine but when the entry changes to the below the grep fails when i dont want it to fail.

Code:
echo "Listen     192.888.22.111:443" > test.out

Also, i do grep -v '#' to ignore lines having # i.e comments but is there a way to check if # is the starting (not necessary the first character considering there are whitespaces before the #) charecter in the line only then it should be ignored else be considered by the grep query.

So....

Quote:
# Listen 192.888.22.111:443
should not be considered

But

Quote:
Listen 192.888.22.111:443 #
should be considered.
 

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LEARN ABOUT NETBSD

zegrep

ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME

     zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files

SYNOPSIS

     zgrep [grep-flags] [--] pattern [files ...]

     zegrep [grep-flags] [--] pattern [file ...]

     zfgrep [grep-flags] [--] pattern [file ...]

DESCRIPTION

     zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).

     The grep-flags and pattern arguments are passed on to grep(1).  If an -e flag is found in the grep-flags, zgrep will not look for a pattern
     argument.

     zegrep calls egrep(1), while zfgrep calls fgrep(1).

EXIT STATUS

     In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.

SEE ALSO

     egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)

AUTHORS

     Thomas Klausner <wiz@NetBSD.org>

BSD
								 December 28, 2003							       BSD
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