Sponsored Content
Top Forums UNIX for Beginners Questions & Answers [BASH] eval command not expanding variables as expected. Post 303041176 by nezabudka on Saturday 16th of November 2019 09:46:13 AM
Old 11-16-2019
you can also read from a file into an associative array
Code:
cat file
(
[apple]=123457
[mango]=123456
[orange]=1234567
)
declare -A arr
m=arr
eval $m=$(<file)
echo ${arr[@]}
1234567 123456 123457
echo ${!arr[@]}
orange mango apple

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

expanding dotted paths to absolute ones in bash or sh

I have a little script to help me manage a gallery of image files. It makes symbolic links to every file in and below the current directory, placing them in a target directory which is passed to the script as a parameter. Unfortunately, the script pukes when I pass a parameter that contains... (4 Replies)
Discussion started by: TanRanger
4 Replies

2. UNIX for Advanced & Expert Users

Expanding Variables in User Input

If have var='$variable' how can I expand $variable. I have tried many thing like duble quotes/braces etc, but nothing worked. I need the solution ASAP. (2 Replies)
Discussion started by: Bsk
2 Replies

3. UNIX for Dummies Questions & Answers

Expanding variables with Ed Bash 3.2.33

Hi, The following code finds the line containing fruits in test.txt and replaces instances of apple with banana. ed -s test.txt <<< $'/fruits/s/apple/banana/g\nw' What I want to do is put variables in the place of fruits, apple and banana. I have tried replacing ' with " to get... (2 Replies)
Discussion started by: de_la_espada
2 Replies

4. Shell Programming and Scripting

Dynamic variables and eval

Hi, I need some direction with the following. The below code is semi-psuedo code which will hopefully make it easier to understand what I am trying to achieve: for i in `echo ${testarray }` do let c=c+1 eval "first$c=$i" while... (4 Replies)
Discussion started by: yonderboy
4 Replies

5. Shell Programming and Scripting

dynamic variables - eval - expand etc.

Hello, so i'm making a script, using dynamic variables and trying to expand them. So far it hasn't worked out too well so it seems that I need some help from you, the elite. Example: #!/bin/sh counter=0 until (($counter>5)) counter2=1 until (($counter2>6)); do if ;... (5 Replies)
Discussion started by: TehOne
5 Replies

6. Shell Programming and Scripting

awk issue expanding variables in ksh script

Hi Guys, I have an issue with awk and variables. I have trawled the internet and forums but can't seem to get the exactt syntax I need. I have tried using awk -v and all sorts of variations but I have hit a brick wall. I have spent a full day on this and am just going round in circles. ... (3 Replies)
Discussion started by: gazza-o
3 Replies

7. Shell Programming and Scripting

Error in eval eval command to print html tags

anyone has any info on why this is complaining??? vivek@vivek-c5e55ef2e ~/TAC $ zoneCounter=1 vivek@vivek-c5e55ef2e ~/TAC $ optUsage1=23% vivek@vivek-c5e55ef2e ~/TAC $ eval eval echo "<th>Zone $zoneCounter </th><th align=\"left\"> \$optUsage$zoneCounter </th>" -bash: syntax error... (1 Reply)
Discussion started by: vivek d r
1 Replies

8. Shell Programming and Scripting

Error in eval eval command to print html tags

anyone has any info on why this is complaining??? vivek@vivek-c5e55ef2e ~/TAC $ zoneCounter=1 vivek@vivek-c5e55ef2e ~/TAC $ optUsage1=23% vivek@vivek-c5e55ef2e ~/TAC $ eval eval echo "<th>Zone $zoneCounter </th><th align=\"left\"> \$optUsage$zoneCounter </th>" -bash: syntax error... (13 Replies)
Discussion started by: vivek d r
13 Replies

9. Shell Programming and Scripting

Possible ksh93 Bug Expanding Variables?

My OS is Linux (kernel 4.08.something) and AIX (7100-04-01-1543), the used ksh versions are: ksh88: Version M-11/16/88f (AIX) ksh93: Version M 93t+ 2009-05-01 (AIX), Version M 93u (Linux) When writing a parser for stanza files in ksh i encountered a rather strange behavior. Here is a... (4 Replies)
Discussion started by: bakunin
4 Replies

10. UNIX for Beginners Questions & Answers

Bash argument not expanding in script

I pass an argument to bash as run. The first command in green executes as expected, however the second in blue fails as the $run does not expand. I tried to escape the variable with \ thinking the quotes were making the literal translation and also "${run}" but both did not work to expand the... (3 Replies)
Discussion started by: cmccabe
3 Replies
DATEFMT_LOCALTIME(3)							 1						      DATEFMT_LOCALTIME(3)

IntlDateFormatter::localtime - Parse string to a field-based time value

	Object oriented style

SYNOPSIS
public array IntlDateFormatter::localtime (string $value, [int &$position]) DESCRIPTION
Procedural style array datefmt_localtime (IntlDateFormatter $fmt, string $value, [int &$position]) Converts string $value to a field-based time value ( an array of various fields), starting at $parse_pos and consuming as much of the input value as possible. PARAMETERS
o $fmt - The formatter resource o $value - string to convert to a time o $position - Position at which to start the parsing in $value (zero-based). If no error occurs before $value is consumed, $parse_pos will contain -1 otherwise it will contain the position at which parsing ended . If $parse_pos > strlen($value), the parse fails immedi- ately. RETURN VALUES
Localtime compatible array of integers : contains 24 hour clock value in tm_hour field EXAMPLES
Example #1 datefmt_localtime(3) example <?php $fmt = datefmt_create( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN ); $arr = datefmt_localtime($fmt, 'Wednesday, December 31, 1969 4:00:00 PM PT', 0); echo 'First parsed output is '; if ($arr) { foreach ($arr as $key => $value) { echo "$key : $value , "; } } ?> Example #2 OO example <?php $fmt = new IntlDateFormatter( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN ); $arr = $fmt->localtime('Wednesday, December 31, 1969 4:00:00 PM PT', 0); echo 'First parsed output is '; if ($arr) { foreach ($arr as $key => $value) { echo "$key : $value , "; } } ?> The above example will output: First parsed output is tm_sec : 0 , tm_min : 0 , tm_hour : 16 , tm_year : 1969 , tm_mday : 31 , tm_wday : 4 , tm_yday : 365 , tm_mon : 11 , tm_isdst : 0 , SEE ALSO
datefmt_create(3), datefmt_format(3), datefmt_parse(3), datefmt_get_error_code(3), datefmt_get_error_message(3). PHP Documentation Group DATEFMT_LOCALTIME(3)
All times are GMT -4. The time now is 04:36 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy