I have different files and i need to split the files in that folder split in to 8 parts with equal number of lines....!
any fastest way of doing this in awk.
for an example i have a file called "BillingDetails_BaseFile.csv" with total line count 65536 and i need to split in to 8 parts with each file having 8192 (8192*8=65536). if 65538,last two lines can be ignored. i had a logic for this but its taking long time for this.
any fastest way in awk is appreciated.
my code:
any fastest way just specifying the folder name it should go each file and look for line count and split the 8 parts with equal number of lines.
Any help in awk is appreciated.
Hello everyone,
I have a big folder in a linux server that contains dozen of big files (total folder size ~ 50 GB)
I have a couple of files of 2.5 GB and some others from 100 MB to 1 GB. (that said it's obvious that it's impossible having two 2.5 GB files in one dvd)
The purpose is to... (7 Replies)
Hey guys,
Sorry for the basic question but I have a lot of files that I want to separate into groups based on filenames which I can then cat together. Eg I have:
(a_b_c.txt)
WB34_2_SLA8.txt
WB34_1_SLA8.txt
WB34_1_DB10.txt
WB34_2_DB10.txt
WB34_1_SLA8.txt
WB34_2_SLA8.txt
77_1_SLA8.txt... (1 Reply)
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2013101000.
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after reaching 31 it becomes 00 and increments 10... (31 Replies)
Hi all:
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I Am connected to Whatbox.ca Seed Box Via SSH!!
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Hi, I have a file like this:
aaa 123
aaa 223
aaa 225
bbb 332
bbb 423
bbb 6755
bbb 324
ccc 112
ccc 234
ccc 897
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split -l 3
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Hi Team,
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Eg:
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