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UNIX for Beginners Questions & Answers
Reading a file line by line and print required lines based on pattern
Post 303040535 by MadeInGermany on Thursday 31st of October 2019 02:59:53 AM
10-31-2019
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1. Shell Programming and Scripting
Hi Experts,
Help needed on joining one line above & below to the pattern matched string line.
The input file, required output is mentioned below
Input file
ABCD DEFG5 42.0.1-63.38.31
KKKK iokl IP Connection Available
ABCD DEFG5 42.0.1-63.38.31
... (7 Replies)
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Hi all,
on Solaris 10, I'd like to print a range of lines starting at pattern but also including the very first line before pattern.
the following doesn't print the range starting at pattern and going down to the end of file: cat <my file> | sed -n -e '/<pattern>{x;p;}/'
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Hi,
I have got the below requirement. please suggest.
I have a file like,
Processing Item is:
/data/ing/cfg2/abc.txt
/data/ing/cfg3/bgc.txt
Processing Item is:
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$ cat file.log
Message Number = : Sending message 10:50:16^|^reqhdr.dummyid^=^02^|^reqhdr.timezone^=^GMT+05:30^|^DUMMYREQUEST^=^BH||||||||||||||||||$BD|OL|C|V||DummyAcctNo|02||24/12/2011|ST_DDM|DDM||||||||reqUUID110612105016$BT||||||||||||||||||$] Length
I have the above line in the... (4 Replies)
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Hi,
I have a file as below
This is the line one
This is the line two
<\XMLTAG>
This is the line three
This is the line four
<\XMLTAG>
Output of the SED command need to be as below.
This is the line one
This is the line two
<\XMLTAG>
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Data:
Pattern Data Data Data
Data Data Data
Data Data Data
...
With awk, how do I print the pattern matching line, then the subsequent lines following the pattern matching line. Varying number of lines following the pattern matching line. (9 Replies)
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Reading line by line from live log file using while loop and considering only those lines start from
Hi,
I want to read a live log file line by line and considering those line which start from time stamp;
Below code I am using, which read line but throws an exception when comparing line that does not contain error code
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Hi,
I have a file like below.
1,2,3,4,5,6,7,8,9I would like to print or copied to a file based of line count in perl
If I gave a condition 1 to 3 then it should iterate over above file and print 1 to 3 and then again 1 to 3 etc.
output should be
1,2,3
4,5,6
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Hello Experts , require help . See below output:
File inputs
------------------------------------------
Server Host = mike
id rl images allocated last updated density
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Input file:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18 (6 Replies)
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LEARN ABOUT DEBIAN
distrib.pats
DISTRIB.PATS(5) File Formats Manual DISTRIB.PATS(5) NAME
distrib.pats - default values for Usenet Distribution header DESCRIPTION
The file /etc/news/distrib.pats is used to determine the default value of the Distribution header. It consists of a series of lines; blank lines and lines beginning with a number sign (``#'') are ignored. All other lines consist of three fields separated by a colon: weight:pattern:value The first field is the weight to assign to this match. If a newsgroup matches multiple lines, the line with the heighest weight is used. This should be an arbitrary number greater than zero. Unlike other INN files, the order of lines in this file is not important. The second field is the name of the newsgroup or a wildmat(3)-style pattern to specify a set of newsgroups. Multiple patterns are not allowed. The third field is the value that should be used if this line is picked as the best match. It can be an empty string. Programs such as inews(1) that process a user's posting should consult this file, typically by using the DDxxx routines, documented in lib- inn(3). The intent is that all newsgroups to which an article is posted be used to index into this file, and the value with the highest weight should be used as the value of the Distribution header, if none was specified. HISTORY
Written by Rich $alz <rsalz@uunet.uu.net> for InterNetNews. This is revision 1.7, dated 1996/09/06. SEE ALSO
inews(1), libinn(3). DISTRIB.PATS(5)