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Top Forums UNIX for Beginners Questions & Answers How to identify delimiter to find and replace a string with sed? Post 303040515 by duke0001 on Wednesday 30th of October 2019 03:35:43 PM
Old 10-30-2019
RudiC:

To write months verbatim and escape, it didn't work either. I need sed identify months because 4 quarters have 4 different begin date and 4 end date. Hard code will not work. I tried something. Please see all output below. Here, $NEWDATE=01-OCT-2019.

Code:
/home/oracle> sed  "s/[0-3][0-9]-\(JUN\|JUL\|AUG\)-[12][09][0-9]\{2\}/$NEWDATE/" test4.txt
       ep.begin_date, ep.end_date, ep.facility_code,
AND    ep.begin_date <= '01-JUL-2019'
       ep.begin_date, ep.end_date, ep.facility_code,
AND    ep.begin_date <= '01-JUL-2019'
       ep.begin_date, ep.end_date, ep.facility_code,
AND    ep.begin_date <= '01-JUL-2019'

/home/oracle/> sed  "s/[0-3][0-9]\-[a-zA-Z]{3}\-[12][09][0-9]\{2\}/$NEWDATE/" test4.txt
       ep.begin_date, ep.end_date, ep.facility_code,
AND    ep.begin_date <= '01-JUL-2019'
       ep.begin_date, ep.end_date, ep.facility_code,
AND    ep.begin_date <= '01-JUL-2019'
       ep.begin_date, ep.end_date, ep.facility_code,
AND    ep.begin_date <= '01-JUL-2019'

 

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DATETIME.SUB(3) 							 1							   DATETIME.SUB(3)

DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_sub (DateTime $object, DateInterval $interval) Subtracts the specified DateInterval object from the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.sub(3) example Object oriented style <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-20'); date_sub($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-10 Example #2 Further DateTime.sub(3) examples <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-19 13:59:30 1992-08-15 19:56:58 Example #3 Beware when subtracting months <?php $date = new DateTime('2001-04-30'); $interval = new DateInterval('P1M'); $date->sub($interval); echo $date->format('Y-m-d') . " "; $date->sub($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-03-30 2001-03-02 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.SUB(3)
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