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Top Forums UNIX for Beginners Questions & Answers Positional parameters in if statement Post 303040328 by Eric7giants on Saturday 26th of October 2019 04:44:15 PM
Old 10-26-2019
Positional parameters in if statement

I am trying to code an if statement that accepts two parameters and see if those parameters are in another file called teledir.txt. If it already exists in the file, it is to say "Entry Exists". If not, I add it to the file and say "Entry Added". This is the code I have so far:
Code:
if [ $# -eq 2 ]; then

                if grep  "$1:$2" teledir.txt; then
                        echo "Entry exists"

                else
                        echo "$1:$2" >> teledir.txt
                        echo "Entry Added"              
                fi

fi


When I run this, if I enter a name and number that is in the file, it says entry added and places it into the file. I'm new to the command line but what am I missing?
 

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ODBC_PREPARE(3) 							 1							   ODBC_PREPARE(3)

odbc_prepare - Prepares a statement for execution

SYNOPSIS
resource odbc_prepare (resource $connection_id, string $query_string) DESCRIPTION
Prepares a statement for execution. The result identifier can be used later to execute the statement with odbc_execute(3). Some databases (such as IBM DB2, MS SQL Server, and Oracle) support stored procedures that accept parameters of type IN, INOUT, and OUT as defined by the ODBC specification. However, the Unified ODBC driver currently only supports parameters of type IN to stored procedures. PARAMETERS
o $connection_id -The ODBC connection identifier, see odbc_connect(3) for details. o $query_string - The query string statement being prepared. RETURN VALUES
Returns an ODBC result identifier if the SQL command was prepared successfully. Returns FALSE on error. EXAMPLES
Example #1 odbc_execute(3) and odbc_prepare(3) example In the following code, $success will only be TRUE if all three parameters to myproc are IN parameters: <?php $a = 1; $b = 2; $c = 3; $stmt = odbc_prepare($conn, 'CALL myproc(?,?,?)'); $success = odbc_execute($stmt, array($a, $b, $c)); ?> If you need to call a stored procedure using INOUT or OUT parameters, the recommended workaround is to use a native extension for your database (for example, mssql for MS SQL Server, or oci8 for Oracle). SEE ALSO
odbc_execute(3). PHP Documentation Group ODBC_PREPARE(3)
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