I am new to shell, and I am trying to do a if statement like the following:
if ; then
basically it works fine if both arguments of the if are met, however the next elif is:
elif ; then
if the conditions of the elif are met, then it says "final1.sh: line 67: [: too many arguments"
... (6 Replies)
In my ksh script, if the conditions of a if statement are true, then do nothing; otherwise, execute some commands.
How do I write the "do nothing" statement in the following example?
Example:
if (( "$x"="1" && "$y"="a" && "$z"="happy" ))
then
do nothing
else
command
command
fi... (3 Replies)
Hi All,
I am using Unix ksh script.
I need to insert values to a table using the o/p from a slelect statement.
Can anybody Help!
My script looks like tihs.
---`sqlplus -s username/password@SID << EOF
set heading off
set feedback off
set pages 0
insert into ${TB_NAME}_D... (2 Replies)
I can't find anything wrong with this line of code, it works when there is one file in the directory but more than one i get a "too many arguements2 error
if ; then
am i missing something? (3 Replies)
Hello friends,
I have a boubt passing different arguments at a time for any one option in below code.
I would also like to check which option has been selected (any one of i, r, u ) so that whether or not matching argument passed can be verified.
for i and r - install and re-install -... (4 Replies)
I am writing a script in bash and want to perform the operation
I check number of arguments and make a print statement with the passes arguments
If I pass 3 arguments I will do
printf "$frmt" "$1" "$2" "$3"If I have 4 arguments I do
printf "$frmt" "$1" "$2" "$3" "$4"etc (4 Replies)
Hi
Am pretty new to C..
Am trying to pass the arguments from command line and use them in switch case statement..
i have tried the following
#include <stdlib.h>
main(int argc, char* argv)
{
int num=0;
if ( argc == 2 )
num = argv;
printf("%d is the num value",num);
switch ( num )
... (2 Replies)
Hello,
I have a question regarding the usage statement of a script.
I have 2 parameters "--pto" and "--pto_list". To start the script I will need one of them. Both together are not possible.
How this would be printed out within a usage statement?
My suggestion would be:
Usage:... (4 Replies)
Hi folks,
I have a scenario to convert the update statements into insert statements using shell script (awk, sed...) or in database using regex.
I have a bunch of update statements with all columns in a file which I need to convert into insert statements.
UPDATE TABLE_A SET COL1=1 WHERE... (0 Replies)
Discussion started by: dev123
0 Replies
LEARN ABOUT PHP
echo
ECHO(3) 1 ECHO(3)echo - Output one or more stringsSYNOPSIS
void echo (string $arg1, [string $...])
DESCRIPTION
Outputs all parameters.
echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other
language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want
to pass more than one parameter to echo, the parameters must not be enclosed within parentheses.
echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn-
tax only works with the short_open_tag configuration setting enabled.
I have <?=$foo?> foo.
PARAMETERS
o $arg1
- The parameter to output.
o $...
-
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
echo examples
<?php
echo "Hello World";
echo "This spans
multiple lines. The newlines will be
output as well";
echo "This spans
multiple lines. The newlines will be
output as well.";
echo "Escaping characters is done "Like this".";
// You can use variables inside of an echo statement
$foo = "foobar";
$bar = "barbaz";
echo "foo is $foo"; // foo is foobar
// You can also use arrays
$baz = array("value" => "foo");
echo "this is {$baz['value']} !"; // this is foo !
// Using single quotes will print the variable name, not the value
echo 'foo is $foo'; // foo is $foo
// If you are not using any other characters, you can just echo variables
echo $foo; // foobar
echo $foo,$bar; // foobarbarbaz
// Some people prefer passing multiple parameters to echo over concatenation.
echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10);
echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . "
";
echo <<<END
This uses the "here document" syntax to output
multiple lines with $variable interpolation. Note
that the here document terminator must appear on a
line with just a semicolon. no extra whitespace!
END;
// Because echo does not behave like a function, the following code is invalid.
($some_var) ? echo 'true' : echo 'false';
// However, the following examples will work:
($some_var) ? print 'true' : print 'false'; // print is also a construct, but
// it behaves like a function, so
// it may be used in this context.
echo $some_var ? 'true': 'false'; // changing the statement around
?>
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
SEE ALSO print(3), printf(3), flush(3), Heredoc syntax.
PHP Documentation Group ECHO(3)