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Top Forums UNIX for Beginners Questions & Answers Search for Multiple strings in a given date range and print the Group if they exists Post 303040200 by linuxuser999 on Thursday 24th of October 2019 08:55:08 PM
Old 10-24-2019
Search for Multiple strings in a given date range and print the Group if they exists

Hi,

I am Searching for Multiple strings in a given date range and print the Group if they exists. the below is the format:

Code:
[2019/10/16 13:22:47.961][INFO ][ABCDDDDDDD]
-------------------------------------------------------------------------------------------------------------------------
ID: FIRST ID
MESSAGE: Event Message received.
-------------------------------------------------------------------------------------------------------------------------
CONTEXT: {
  "ID" : 1,
  "event" : "something",
  COMMON_TEXT: COMMON
    "valid" : true
}
*************************************************************************************************************************
[2019/10/16 13:23:00.816][INFO ][ABCDDDDDEEEEEEE]
-------------------------------------------------------------------------------------------------------------------------
ID: SECOND ID
MESSAGE: Event Message received.
-------------------------------------------------------------------------------------------------------------------------
CONTEXT: {
  "ID" : 1,
  "event" : "One More thing",
  COMMON_TEXT: COMMON
    "valid" : true
}
*************************************************************************************************************************
[2019/10/16 13:33:00.816][INFO ][ABCDDDDDEEFFFFFFFFFFFFFEEE]
-------------------------------------------------------------------------------------------------------------------------
ID: THIRD ID
MESSAGE: Event Message received.
-------------------------------------------------------------------------------------------------------------------------
CONTEXT: {
  "ID" : 1,
  "event" : "Second thing",
  COMMON_TEXT: COMMON
    "valid" : False
}
*************************************************************************************************************************

SED COMMAND
Code:
sed -n '/2019\/10\/23 12:2[0-2]/{:a;N;/2019\/10\/23 12:3[0-3]/!ba; /FIRST ID/p}'  logfile

- This is working fine, but I wanted to give one more search criteria along with FIRST ID in the group (like something) and if both exists print the group otherwise skip the group.

AWK Command
Code:
awk 'substr($1,2,11)>="2019\/10\/23" && substr($1,2,11)<="2019\/10\/23" && substr($2,1,8)>="12:22:00" && substr($2,1,8)<="12:33:00"' logfile

I am getting only first line with the dates with this group.

I am not a unix expert, can someone please help on this.

 

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DATETIMEIMMUTABLE.FORMAT(3)						 1					       DATETIMEIMMUTABLE.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTimeImmutable.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIMEIMMUTABLE.FORMAT(3)
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