Hai I just want to find a file *.txt in particular direcotry and display the file name puls the content. Do someone know hot to do this, thanks.
I try :
find test/ -name '*.txt' | xargs cat
but It does'nt print out the file name, i want something below print out in my screen :
test/1.txt... (4 Replies)
Hello,
So I sorted my file as I was supposed to:
sort -n -r -k 2 -k 1 file1 | uniq > file2
and when I wrote
> cat file2
in the command line, I got what I was expecting, but in the script itself
...
sort -n -r -k 2 -k 1 averages | uniq > temp
cat file2
It wrote a whole... (21 Replies)
Hi,
I am having trouble getting a combination of commands to work.
I need to traverse through all sub-directories of a certain directory and 'cat' the contents of a particular file in the sub-directories.
The commands on their own work but when I combine them I get no output.
The... (4 Replies)
Hi
I have to find if a pattern is present in a line.
eq
line="dasdasd hello asdasdasd"
Have to find if "hello" is present in the line or not.
Which command to be used?
Thanks (10 Replies)
Hi,
I am creating a script to do a find and replace single/multiple lines in a file with any number of lines.
I have written a logic in a script that reads a reference file say "findrep" and populates two variables $FIND and $REPLACE
print $FIND gives
Hi How r $u
Rahul()
Note:... (0 Replies)
I am trying to delete files older than 60 days from a folder:
find /myfolder/*.dat -mtime +60 -exec rm {} \;
ERROR - argument list too long: find
I can't just give the folder name, as there are some files that I don't want to delete. So i need to give with the pattern (*.dat). I can... (3 Replies)
How can I recursively find all files in a directory and print out the file and first line number of any text blocks that match the below cases?
This would seem to involve find, xargs, *grep, regex, etc.
In summary, I want to find so-called empty "try-catch blocks" that do not contain code... (0 Replies)
Guys, need help.
I have a file that contains something like this:
abc
def
ghi
jkl
I want to print the first and last line of the file and the output should be in a single line.
so, output should be like this:
abc jkl (3 Replies)
Hi all,
How can i display the middle line of a file using a single line command? (6 Replies)
Discussion started by: Lakme Pemmaiah
6 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)