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Top Forums Shell Programming and Scripting Syntax error in subtraction in Bash Post 303040005 by ngabrani on Monday 21st of October 2019 12:50:50 PM
Old 10-21-2019
Syntax error in subtraction in Bash

I am sharing a code snippet.
Code:
for (( i=0; i<=$(( $count -1 )); i++ ))
do

	first=${barr2[$i]}
	search=${barr1[$i]}
        echo $first
	echo "loop begins"
	for (( j=0; j<=5000; j++ ))
	do
		if [[ ${harr1[j]} == $search ]]; then
			echo $j
			break;
		fi

	done
	second=${harr2[$j]}	
	echo $second
	
	diff=$((second-first))
	echo "diff" 
	echo $diff
done

I am getting a syntax error in line of subtraction that says something like:
syntax error: invalid arithmetic operator (error token is ".0985146")

This is the line that gives error.
Code:
	diff=$((second-first))

Appreciate your help.
 

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Sub::Quote(3)						User Contributed Perl Documentation					     Sub::Quote(3)

NAME
Sub::Quote - efficient generation of subroutines via string eval SYNOPSIS
package Silly; use Sub::Quote qw(quote_sub unquote_sub quoted_from_sub); quote_sub 'Silly::kitty', q{ print "meow" }; quote_sub 'Silly::doggy', q{ print "woof" }; my $sound = 0; quote_sub 'Silly::dagron', q{ print ++$sound % 2 ? 'burninate' : 'roar' }, { '$sound' => $sound }; And elsewhere: Silly->kitty; # meow Silly->doggy; # woof Silly->dagron; # burninate Silly->dagron; # roar Silly->dagron; # burninate DESCRIPTION
This package provides performant ways to generate subroutines from strings. SUBROUTINES
quote_sub my $coderef = quote_sub 'Foo::bar', q{ print $x++ . " " }, { '$x' => }; Arguments: ?$name, $code, ?\%captures, ?\%options $name is the subroutine where the coderef will be installed. $code is a string that will be turned into code. "\%captures" is a hashref of variables that will be made available to the code. See the "SYNOPSIS"'s "Silly::dagron" for an example using captures. options o no_install Boolean. Set this option to not install the generated coderef into the passed subroutine name on undefer. unquote_sub my $coderef = unquote_sub $sub; Forcibly replace subroutine with actual code. Note that for performance reasons all quoted subs declared so far will be globally unquoted/parsed in a single eval. This means that if you have a syntax error in one of your quoted subs you may find out when some other sub is unquoted. If $sub is not a quoted sub, this is a no-op. quoted_from_sub my $data = quoted_from_sub $sub; my ($name, $code, $captures, $compiled_sub) = @$data; Returns original arguments to quote_sub, plus the compiled version if this sub has already been unquoted. Note that $sub can be either the original quoted version or the compiled version for convenience. inlinify my $prelude = capture_unroll { '$x' => 1, '$y' => 2, }; my $inlined_code = inlinify q{ my ($x, $y) = @_; print $x + $y . " "; }, '$x, $y', $prelude; Takes a string of code, a string of arguments, a string of code which acts as a "prelude", and a Boolean representing whether or not to localize the arguments. capture_unroll my $prelude = capture_unroll { '$x' => 1, '$y' => 2, }; Generates a snippet of code which is suitable to be used as a prelude for "inlinify". The keys are the names of the variables and the values are (duh) the values. Note that references work as values. CAVEATS
Much of this is just string-based code-generation, and as a result, a few caveats apply. return Calling "return" from a quote_sub'ed sub will not likely do what you intend. Instead of returning from the code you defined in "quote_sub", it will return from the overall function it is composited into. So when you pass in: quote_sub q{ return 1 if $condition; $morecode } It might turn up in the intended context as follows: sub foo { <important code a> do { return 1 if $condition; $morecode }; <important code b> } Which will obviously return from foo, when all you meant to do was return from the code context in quote_sub and proceed with running important code b. perl v5.16.2 2012-07-04 Sub::Quote(3)
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