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Top Forums UNIX for Beginners Questions & Answers File manipulation place 0 before the number using sed Post 303039601 by RudiC on Thursday 10th of October 2019 04:26:10 AM
Old 10-10-2019
In case there are other occurrences of three letters followed by a space and a digit, you might want to narrow down the search pattern to the locale months:
Code:
sed -r "s/($(locale abmon | tr ';' '|')) ([[:digit:]] )/\1 0\2/g" file

Be aware that you need sed to recognize / handle EREs for this simple tr approach.
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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