I used this SQL query to fetch business_day and Date_digits into shell variables jdate1 and jdate2. Then use sed to replace them. It worked well.
If using my SQL query, how it work with your awk code?. My query like this:
This output is : 2019304
This output is: 1910.304,
Then I used:
The two files has been replaced with correct Julian date digits in variables. I redirect output to a new file because Solaris do not support sed -i to direct change in place. Then I can overwrite the file with mv back to original name for another Application to use. I want to learn from you how to use your code awk to do the work. Thanks.
There is a service that runs that we call multi-streaming that calls a shell script multiple times simultaneously. In this shell script is the following line:
tr '\r' '\n' < $POLLFILE.OUT | sed '/0000000000000016000A/d' > $POLLFILE
When I run this manually it produces the desired results, but... (6 Replies)
So I am working on command line and I have a file that is spaced by tabs like:
one countMe
two countMEtoo
three COUNTMEthree
What I want to do is read in that file, and replace the second column contents with the length of the string in that column.
one 7
two 10... (14 Replies)
Hello i need some help with the usage of sed.
Situation : 2 textfiles, file.in , file.out
In the first textfile which is called file.in are the words for the substitution.
Every word is in a new-line like :
Firstsub
Secondsub
Thridsub
...
In the second textflie wich is called file.out is... (5 Replies)
Hi
I have a problem when i use awk or sed to replace characters in file.
For example when I want to replace line like this :
00000O120100512 1.70 1.59 0.00 +7.280
I want to get a new line :
0000000O120100512 1.70 1.59 13.56 +7.280
In ksh :
awk... (1 Reply)
Hi,
How I can replace last 8 ZEROS with 22991231?
19523479811841494432A2013052700000000
19523479811730333980A2013052700000000
19523479811417044397A2013052700000000
19523479811205895810C2013010120130131
A9523479811205895810A2013020120130228
19523479811205895810I2013030120130331... (9 Replies)
Hi,
Need a help to replace a word if a pattern is found between the delimiters preferably using SED or AWK.
below is the sample file that iam dealing with, need to match pattern 'application' if found replace the whole word between the delimiters and also print the lines that don't match.... (1 Reply)
My code below will print only the email address from all lines. I want to convert it with sed or awk.. also what if i just want to find only filenames.
cat LIS_EMAIL | perl -wne'while(/+@+\w+/g){print "$&\n"}'
Hoping to extract the filename such us .exe, .bin. From file that has scrambled... (8 Replies)
Hi All ,
I am having an input file as stated below
5728 U_TOP_LOGIC/U_CM0P/core/u_cortexm0plus/u_top/u_sys/u_core/r03_q_reg_20_/Q 011
611 U_TOP_LOGIC/U_CM0P/core/u_cortexm0plus/u_top/u_sys/u_core/r04_q_reg_20_/Q 011
3486... (4 Replies)
Hello Everyone,
I have many files like so:
file1.txt
file2.txt
file3.txt
Within each file I have many lines of random text separated by commas like so:
abcAAA,123,defAA,456777,ghiA,789
jklB,101,mnoBBB,11211,pqrB,13111
stuCC,415,vwxCCCC,161,yzaC,718
I am trying to use SED or AWK to... (4 Replies)