Please don't full quote forum posts. Please only quote the short passage of text you're relating to. Refrain from full quoting because it adds redundant information and makes the thread harder to read.
regarding quoting #1
It's always a good idea to quote parameters. Else the shell will split your parameters at whitespace. For sure it splits your json-object - which is not what you want. Do it that way:
regarding quoting #2
This(single quotes) '$comment' does not replace $comment with the value contained in $comment. This(double quotes) "$comment" does.
regarding quoting #3
Quote:
You mean to add double quotes when I run the command? Because I have already added double quotes when I assigned the variable due to the existence of 2 separate words. Won't "$comment" expand to ""Periodic payments""? Or should I remove the double quotes at the assignment of the comment variable?
You misunderstood the concept of quoting a bit. If you assign a variable like that: variable="my value", the content of $variable is not "my value" it is my value(without the quotes). The quotes just protect the content from word splitting. If you leave the quotes out, it would be a complete different command. If you run this command: variable=my value this means assign my to variable for the next program call and call the program named value.
You can only get quotes as data into some variable if you quote it. ;-) like this quotes_variable='"' or like this: quotes_variable="\"".
I recommend to read a bit about quoting to fully understand the concept, as it is really important!
I couldn't find an existing thread that addressed this question, so hopefully this isn't redundant with anything previously posted. Here goes:
I am writing a C-Shell script that runs a program that takes an arbitrary number of parameters:
myprog -a file1 \
-b file2 \
-c file3 ... \
-n... (2 Replies)
I need help in writing a BASH SCRIPT of ls command.
for example:
$ ./do_ls.sh files
f1.txt
f2.jpeg
f3.doc
$ ./do_ls.sh dirs
folder1
folder2
folder3
My attempt:
#!/bin/bash
#
if test $# -d file
then
echo $dirs
else (3 Replies)
Hello,
I would like to modify an existing script of mine that uses a manually defined "MCVERSION" variable and make it define that variable instead based on this JSON file stored online:
https://s3.amazonaws.com/Minecraft.Download/versions/versions.json
Within that JSON, I 'm looking for... (4 Replies)
All,
Have a weird issue where i need to generate a report from GitHub monthly detailing user accounts and the last time they logged in. I'm using a windows box to do this (work issued) and would like to know if anyone has any experience scripting for GitAPI using windows / cygwin / powershell?... (9 Replies)
I am trying to automate editing of a json file using bash script.
The file I initially receive is
{
"appMap": {
"URL1": {
"name": "a"
},
"URL2": {
"name": "b"
},
"URL3": {
"name": "c"
},
}
WHat I would like to do is replace... (5 Replies)
i have a json data that looks like this:
{
"ip": "16.66.35.10",
"hostname": "No Hostname",
"city": "Stepney",
"region": "England",
"country": "GB",
"loc": "51.57,-0.0333",
"org": "AS6871 British Telecommunications PLC",
"postal": "E1"
}
im looking for a way to assign... (9 Replies)
Hello guys,
I want to parse a JSON file in order to get the data in a table form.
My JSON file is like this:
{
"document":{
"page":
},
{
"column":
}
]
},
{
... (6 Replies)
One of the great thing about unix is the ability to pipe multiple programs together to manipulate data. Plain, unstructured text is the most common type of data that is passed between programs, but these days JSON is becoming more popular.
I thought it would be fun to pipe together some command... (1 Reply)
Hi All,
I am new to shell scripting, Need your help in creating a shell script which converts any unix command output to JSON format output.
example:
sample df -h command ouput :
Filesystem size used avail capacity Mounted
/dev/dsk/c1t0d0s0 8.1G 4.0G 4.0G 50% /... (13 Replies)