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Top Forums Shell Programming and Scripting Building JSON command with bash script Post 303038977 by psysc0rpi0n on Wednesday 18th of September 2019 03:58:51 PM
Old 09-18-2019
Quote:
Originally Posted by stomp
Notes:
  • maybe you can spare the escaping of " if you mix ' (single quotes) and " (double quotes).
  • simple shell scripting will suffice for what you want to achieve, jq seems not necessary(but hey! Read the docs maybe it's way simpler! I'm not an jq expert, I just use it occasionally)
  • if you want to know if jq accepts the input, in other words to validate json, just pipe your data into jq . like echo "$data" | jq .. jq will complain if the data is not well formed.
But I cannot do it this way because this "com_params" variable that I set to store the command parameters is seen as a single long string, and if I do it this way, the app that parses the command to JSON complains.

How do you say this can be done with a simple bash script without using 'jq' ? Please give me a hint because I'm not getting there. I'm around this for like 2 or 3 weeks and I can't find a way to make the command to be accepted by the daemon that parses the command!

Note:
This is the code I actually have:
(I can't post links yet)
Search for my nick in Github anf for "TugaRevoBTC" repository if you want to see the code!
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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