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Full Discussion: awk - multiple and nested if-then-else
Top Forums Shell Programming and Scripting awk - multiple and nested if-then-else Post 303038727 by jcdole on Thursday 12th of September 2019 10:52:52 AM
Old 09-12-2019
Quote:
Originally Posted by RudiC
Not clear. The result you present is exactly what one would expect once your code has been rearranged like

Code:
awk -v a="$ROW_ID_TO_SEARCH" '
        {if ($1 == a)   if ($2 == "") printf ("ID_NULL --> ROW_ID:%s\tVALUE:%s\n",      $1, $2)
           else         if ($2 != "") printf ("ID_NOLT_NULL --> ROW_ID:%s\tVALUE:%s\n", $1, $2)
    }
' file

If your search pattern is not found AND $2 holds a value, print that "ID_NOLT_NULL" - line.

What is your desire? What am I missing here?
Than k you for your quick posting.3


I have found this rules when googleing :
Code:
if(conditional-expression1)
    action1;
else if(conditional-expression2)
    action2;
else if(conditional-expression3)
    action3;
    .
    .
else
    action n;

What I would like to do if possible is ( don't take care about the {} syntax; it is just to explain my thought) :


Code:
if(conditional-expression1)
    { if(conditional-expression4)        action4 ;   

    else if(conditional-expression5)        action5 ;

    else if(conditional-expression2)
        { if(conditional-expression6)             action6 ;   

         else if(conditional-expression7)             action7 ; } }


    else if(conditional-expression2)
      action2;  
    else if(conditional-expression3)
       action3 ;
    .
    . }
else
    action n;

I would like to add a sub level block of if-then-else any where.

--- Post updated at 17:52 ---

Quote:
Originally Posted by RudiC
Not clear. The result you present is exactly what one would expect once your code has been rearranged like

Code:
awk -v a="$ROW_ID_TO_SEARCH" '
        {if ($1 == a)   if ($2 == "") printf ("ID_NULL --> ROW_ID:%s\tVALUE:%s\n",      $1, $2)
           else         if ($2 != "") printf ("ID_NOLT_NULL --> ROW_ID:%s\tVALUE:%s\n", $1, $2)
    }
' file

If your search pattern is not found AND $2 holds a value, print that "ID_NOLT_NULL" - line.

What is your desire? What am I missing here?

To explain what i want I am going to use pseudo code so forget missing ';' or missing {} :
Code:
awk -v a="$ROW_ID_TO_SEARCH" '
 {if ($1 == a)        # everything now depend of the fact that $1 == a
 if ($2 == "") printf ("ID_NULL --> ROW_ID:%s\tVALUE:%s\n",      $1, $2)      # because $1 == a  &&  $2 == ""
else
if ($2 != "") printf ("ID_NOLT_NULL --> ROW_ID:%s\tVALUE:%s\n", $1, $2)  # because $1 == a  &&  $2 != ""

} else {

# now here $1 != a and then nothing to do

}' INPUT_FILE

and the result should be now :
Code:







because the row id to search is not in the input file







        

        

       



            
            
            
            


            

            
            




            
                
            

            

        



        


        


 


        

         



	

           

                  

	
                
				
					
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