I'm trying to use a bash script for a psych experiment that involves listening to sound files and responding. If I have something like the code below, how can I make sure that a key press is assigned to RESPONSE only after the second echo statement?
Also, maybe this is the same question, but how can I make sure that if there are accidentally two or more key presses, that the extra presses are ignored instead of getting assigned to RESPONSE on the next iteration(s)?
I am trying to create a shell (ksh) which has two "read" commands, one which reads a line from a file and another which is inside a loop that reads user input from a keyboard. However, the "read" command inside the loop uses the input from the file and it does not get the user input from keyboard.... (3 Replies)
Hello all,
How can i have a user input that reads like this:
echo -n "Please enter a & b:" 10 20
read a
read b
echo $a
echo $b
10
20
right now i have divided it into two echos, like
echo -n "a: "
echo -n "b: " (1 Reply)
I'm trying to set up a script that takes user input and validates that the user input was entered correctly.
So far I have this:
while :
do
echo "Please enter your name."
read NAME
if
then
echo "You have not entered a name."
echo... (13 Replies)
If I want all user input to start with " : " if not display error
or what I asking is how to do if statement that control a first letter of string that we want to start with. and not worry about the rest
Thank (1 Reply)
Hi,
echo "Enter file name of input file list along with absolute path : "
read inputFileList
if
then
for string in `cat inputFileList`
do
echo $string
done
else
echo " file does not exist"
fi
From the above code, if the user enters a invalid file... (1 Reply)
i have a script which takes input from user, if user gives either Y/y then it should continue, else it should quit by displaying user cancelled.
#!/bin/sh
echo " Enter your choice to continue y/Y OR n/N to quit "
read A
if
then
echo " user requested to continue "
##some commands... (7 Replies)
$Input_filename=$ARGV;
if (!-d $Input_filename && ! -e $Input_filename)
{
print "USAGE: Please enter '$ABCD/def/dsed.txt' as an arguement \n";
exit;
}
1. Input Is suppose to be something like "$ABCD/def/dsed.txt".
if the input is wrong the script should throw an ERROR message.... (2 Replies)
Why does removing "rhgb quiet" from the kernel boot parameters control whether or not the commands I enter are displayed in single user mode ?
For instance, if I do not remove "rhgb quiet", when I am in single user mode, whatever command I type will not be displayed on the screen.
The... (0 Replies)
I am trying to allow a user to enter in text and then store that text in a variable $gene to run in an awk command in which those values are used to run some calculations. I am getting syntax errors however, when I try. Thank you :).
The awk runs great if it is a pre-defined file that is used,... (7 Replies)
Discussion started by: cmccabe
7 Replies
LEARN ABOUT PHP
echo
ECHO(3) 1 ECHO(3)echo - Output one or more stringsSYNOPSIS
void echo (string $arg1, [string $...])
DESCRIPTION
Outputs all parameters.
echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other
language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want
to pass more than one parameter to echo, the parameters must not be enclosed within parentheses.
echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn-
tax only works with the short_open_tag configuration setting enabled.
I have <?=$foo?> foo.
PARAMETERS
o $arg1
- The parameter to output.
o $...
-
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
echo examples
<?php
echo "Hello World";
echo "This spans
multiple lines. The newlines will be
output as well";
echo "This spans
multiple lines. The newlines will be
output as well.";
echo "Escaping characters is done "Like this".";
// You can use variables inside of an echo statement
$foo = "foobar";
$bar = "barbaz";
echo "foo is $foo"; // foo is foobar
// You can also use arrays
$baz = array("value" => "foo");
echo "this is {$baz['value']} !"; // this is foo !
// Using single quotes will print the variable name, not the value
echo 'foo is $foo'; // foo is $foo
// If you are not using any other characters, you can just echo variables
echo $foo; // foobar
echo $foo,$bar; // foobarbarbaz
// Some people prefer passing multiple parameters to echo over concatenation.
echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10);
echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . "
";
echo <<<END
This uses the "here document" syntax to output
multiple lines with $variable interpolation. Note
that the here document terminator must appear on a
line with just a semicolon. no extra whitespace!
END;
// Because echo does not behave like a function, the following code is invalid.
($some_var) ? echo 'true' : echo 'false';
// However, the following examples will work:
($some_var) ? print 'true' : print 'false'; // print is also a construct, but
// it behaves like a function, so
// it may be used in this context.
echo $some_var ? 'true': 'false'; // changing the statement around
?>
NOTES
Note
Because this is a language construct and not a function, it cannot be called using variable functions.
SEE ALSO print(3), printf(3), flush(3), Heredoc syntax.
PHP Documentation Group ECHO(3)