Dear All
I have a file like this
112534554
446538656
444695656
225696966
226569744
228787874
113536566
443533535
222564552
115464656
225445345
225533234
I want to cut the file into different parts where the first two columns are '11' . The first two columns will be either... (3 Replies)
All,
i need a script which can zip the all files which are in directories and its subdirectories
for example:
dir1 contains file1,file2,dir1a,dir1b
now dir1a also contains fil11,fil12 ,dirab
so script should look for files in dir or sub dir till files not found and... (2 Replies)
Hello UNIX experts,
I have 124 text files in a directory. I want to extract the 45678th line of all the files sequentialy by file names. The extracted lines should be printed in the output file on seperate lines.
e.g. The input Files are one.txt, two.txt, three.txt, four.txt
The cat of four... (1 Reply)
Hi everyone, this is my first post here, I hope someone can help me.
I have a file which I need to delete characters '_F3' from the end of the text in the first column. The problem is that the characters may also occur elsewhere in the file (i.e. second columns onwards). I tried sed (thinking I... (6 Replies)
I have n files and I am using cat to combine them in to one.
Before that simply add the name of the output file to 4th column and then print the output. Is it possible ?
input1
chr start end name 0 + key
input2
chr start end name 0 + key
inputn... (1 Reply)
I have an awk script to find the maximum value of the 2nd column of a 2 column datafile, but I need to find the top 5 maximum values of the 2nd column.
Here is the script that works for the maximum value.
awk 'BEGIN { subjectmax=$1 ; max=0} $2 >= max {subjectmax=$1 ; max=$2} END {print... (3 Replies)
Is there an awk script that can easily perform the following operation?
I have a data file that is in the format of
1944-12,5.6
1945-01,9.8
1945-02,6.7
1945-03,9.3
1945-04,5.9
1945-05,0.7
1945-06,0.0
1945-07,0.0
1945-08,0.0
1945-09,0.0
1945-10,0.2
1945-11,10.5
1945-12,22.3... (3 Replies)
Hi
I have 5 columns like this
a b c d e
f g h i j
k l m n o
From 2nd column till the 5th column of every record, I would like to transpose them as rows, so my output file contains only one row
a
b
c
d
e
f
g
h
i
j (9 Replies)
Hi,
I have a requirement to search for a pattern in each line in a file and remove the in between words till the 3rd occurrence of double quote (").
Ex: CREATE TABLE "SCHEMANAME"."AMS_LTV_STATUS"
(Note: "SCHEMANAME" may changes for different schemas. Its not a fixed value)
I need to... (2 Replies)
Hi,
My input files is like this
axis1 0 1 10
axis2 0 1 5
axis1 1 2 -4
axis2 2 3 -3
axis1 3 4 5
axis2 3 4 -1
axis1 4 5 -6
axis2 4 5 1
Now, these are my following tasks
1. Print a first column for every two rows that has the same value followed by a string.
2. Match on the... (3 Replies)
Discussion started by: jacobs.smith
3 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)