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Top Forums UNIX for Beginners Questions & Answers “sed” replace date in text file with current date Post 303038198 by pradeepp on Tuesday 27th of August 2019 04:18:45 PM
Old 08-27-2019
sed -i 's/$$EDWS_DATE_INSERT *=.*/$$EDWS_DATE_INSERT='"$(date `+%y%m%d`)"'/' abc.txt

-ksh: +%y%m%d: not found [No Such File or directory]

gave this error but it worked ; however the date format ended up being timestamp its did not format to date

Code:
line1
line2
line3
$$EDWS_DATE_INSERT=Tue Aug 27 15:15:15 CDT 2019
line4
 

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DATETIMEIMMUTABLE.FORMAT(3)						 1					       DATETIMEIMMUTABLE.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTimeImmutable.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIMEIMMUTABLE.FORMAT(3)
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