How to assign a value to a variable in awk scripting? Post: 303038184

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How can I assign awk's variable to shell script's variable?

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perl::critic::policy::builtinfunctions::prohibitlvaluesubstr

Perl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSuUser(Contributed Perl DocPerl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSubstr(3pm)

NAME

       Perl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSubstr - Use 4-argument "substr" instead of writing "substr($foo, 2, 6) = $bar".

AFFILIATION

       This Policy is part of the core Perl::Critic distribution.

DESCRIPTION

       Conway discourages the use of "substr()" as an lvalue, instead recommending that the 4-argument version of "substr()" be used instead.

	   substr($something, 1, 2) = $newvalue;     # not ok
	   substr($something, 1, 2, $newvalue);      # ok

       The four-argument form of "substr()" was introduced in Perl 5.005.  This policy does not report violations on code which explicitly
       specifies an earlier version of Perl (e.g. "use 5.004;").

CONFIGURATION

       This Policy is not configurable except for the standard options.

SEE ALSO

       "substr" in perlfunc (or "perldoc -f substr").

       "4th argument to substr" in perl5005delta

AUTHOR

       Graham TerMarsch <graham@howlingfrog.com>

COPYRIGHT

       Copyright (c) 2005-2011 Graham TerMarsch.  All rights reserved.

       This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.

perl v5.14.2							    2012-06-07	 Perl::Critic::Policy::BuiltinFunctions::ProhibitLvalueSubstr(3pm)

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