Dear friends,
please tell me how to find the files which are existing in the current directory, but it sholud not search in the sub directories..
it is like this,
current directory contains
file1, file2, file3, dir1, dir2
and dir1 conatins
file4, file5
and dir2 contains
file6,... (9 Replies)
Hi,
I have line in input file as below:
3G_CENTRAL;INDONESIA_(M)_TELKOMSEL;SPECIAL_WORLD_GRP_7_FA_2_TELKOMSEL
My expected output for line in the file must be :
"1-Radon1-cMOC_deg"|"LDIndex"|"3G_CENTRAL|INDONESIA_(M)_TELKOMSEL"|LAST|"SPECIAL_WORLD_GRP_7_FA_2_TELKOMSEL"
Can someone... (7 Replies)
I want to list all files/lines which except those which contain the pattern ' /proc/' OR ' /sys/' (mind the leading blank).
In a first approach I coded:
find / -exec ls -ld {} | grep -v ' /proc/| /sys/' \; > /tmp/list.txt
But this doesn't work. I got an error (under Ubuntu):
grep:... (5 Replies)
Hello everyone
Sorry I have to add another sed question. I am searching a log file and need only the first 2 occurances of text which comes after (note the space) "string " and before a ",". I have tried
sed -n 's/.*string \(*\),.*/\1/p' filewith some, but limited success. This gives out all... (10 Replies)
I have a bunch of random character lines like ABCEDFG. I want to find all lines with "A" and then change any "E" to "X" in the same line. ALL lines with "A" will have an "X" somewhere in it. I have tried sed awk and vi editor. I get close, not quite there. I know someone has already solved this... (10 Replies)
I am new to bash/shell scripting.
I want to find all the files in directory and subdirectories, which are not ends with “.zip” and which are contains in the file name “*.log*” or “*.out*”.
I know below command to get the files which ends with “.log”; but I need which are not ends with this... (4 Replies)
These three finds worked as expected:
$ find . -iname "*.PDF"
$ find . -iname "*.PDF" \( ! -name "*_nobackup.*" \)
$ find . -path "*_nobackup*" -prune -iname "*.PDF"
They all returned the match:
./folder/file.pdf
:b:
This find returned no matches:
$ find . -path "*_nobackup*" -prune... (3 Replies)
Hello.
System : opensuse leap 42.3
I have a bash script that build a text file.
I would like the last command doing :
print_cmd -o page-left=43 -o page-right=22 -o page-top=28 -o page-bottom=43 -o font=LatinModernMono12:regular:9 some_file.txt
where :
print_cmd ::= some printing... (1 Reply)
I am trying find files in sub dir with certain tags using tag command, and add the period to the beginning. I can't use chflags hidden {} cause it doesn't add period to the beginning of the string for web purpose. So far with my knowledge, I only know mdfind or tag can be used to search files with... (6 Replies)
Discussion started by: Nexeu
6 Replies
LEARN ABOUT PHP
datefmt_set_lenient
DATEFMT_SET_LENIENT(3) 1 DATEFMT_SET_LENIENT(3)IntlDateFormatter::setLenient - Set the leniency of the parser
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::setLenient (bool $lenient)
DESCRIPTION
Procedural style
bool datefmt_set_lenient (IntlDateFormatter $fmt, bool $lenient)
Define if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly. Enabling lenient parsing allows
the parser to accept otherwise flawed date or time patterns, parsing as much as possible to obtain a value. Extra space, unrecognized
tokens, or invalid values ("February 30th") are not accepted.
PARAMETERS
o $fmt
- The formatter resource
o $lenient
- Sets whether the parser is lenient or not, default is TRUE (lenient).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
datefmt_set_lenient(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/MM/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
datefmt_set_lenient($fmt, false);
echo "
Now lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : ".intl_get_error_message();
echo "
Error_code is : ".intl_get_error_code();
}
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/MM/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
$fmt->setLenient(FALSE);
echo "
Now lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
The above example will output:
lenient of the formatter is : TRUE
Trying to do parse('35/13/1971').
Result is : 66038400
Now lenient of the formatter is : FALSE
Trying to do parse('35/13/1971').
Result is :
Error_msg is : Date parsing failed: U_PARSE_ERROR
Error_code is : 9
SEE ALSO datefmt_is_lenient(3), datefmt_create(3).
PHP Documentation Group DATEFMT_SET_LENIENT(3)