Did you try the proposal given (based on your non-representative sample in post #1) with your revised data, perhaps with revised search patterns?
No, because as far as the few I knew about sed :
/^§/ stand for "§" at beginning of line
/ɸ$/ stand for "ɸ" at end of ligne
that is not the case for my file heade
Quote:
Originally Posted by RudiC
1. The #! /bin/bash shebang is pointless on line 11.
The shebang is at line 1 not 11
It is the first line of the header file
Quote:
Originally Posted by RudiC
2. Not mentioned in your sample.
Sorry I don't understand
Quote:
Originally Posted by RudiC
4. The address range used in the proposal doesn't care for the numner of lines between start and end.
Of course. This is the question.
How to replace all the characters ( whichever they are ) from the first "§" (including it) up to the last (including it) with the defined block of text
The number of line lines is useless.
There is a start point : the first "§"
There is an end point : the second "ɸ" ( or any "ɸ" followed by "[[:blank:]]#")
Doing that manually with a text editor :
1) copy (from somewhere)
the new text from the first "§" up to the last "ɸ".
2) Select
In the current file, select the text from the first "§" up to the last "ɸ". Don't care about the number of lines.
3) paste
over the selection paste the text previously copied.
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