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Top Forums UNIX for Beginners Questions & Answers How to convert any shell command output to JSON format? Post 303037795 by balu1234 on Tuesday 13th of August 2019 05:11:45 PM
Old 08-13-2019
How to convert any shell command output to JSON format?

Hi All,

I am new to shell scripting, Need your help in creating a shell script which converts any unix command output to JSON format output.
example:
sample df -h command ouput :

Code:
Filesystem   size   used   avail   capacity   Mounted
/dev/dsk/c1t0d0s0   8.1G   4.0G   4.0G   50%   /
/devices   0K   0K   0K   0%   /devices
ctfs   0K   0K   0K   0%   /system/contract
proc   0K   0K   0K   0%   /proc
mnttab   0K   0K   0K   0%   /etc/mnttab
swap   3.1G   836K   3.1G   1%   /etc/svc/volatile
objfs   0K   0K   0K   0%   /system/object
sharefs   0K   0K   0K   0%   /etc/dfs/sharetab
/usr/lib/libc/libc_hwcap1.so.1   8.1G   4.0G   4.0G   50%   /lib/libc.so.1
fd   0K   0K   0K   0%   /dev/fd
swap   3.1G   84K   3.1G   1%   /tmp
swap   3.1G   32K   3.1G   1%   /var/run
/dev/dsk/c1t0d0s7   11G   11M   11G   1%   /export/home
/vol/dev/dsk/c0t0d0/sol_10_113_x86   2.1G   2.1G   0K   100%   /cdrom/sol_10_113_x86

Desired output in JSON format:

Code:
{
"Filesystem": "/dev/dsk/c1t0d0s0",
"size": "8.1G",
"used": "4.0G",
"avail": "4.0G"
"capacity": "50%",
"Mounted": "/"
}

 

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JSON_XS(1p)						User Contributed Perl Documentation					       JSON_XS(1p)

NAME
json_xs - JSON::XS commandline utility SYNOPSIS
json_xs [-v] [-f inputformat] [-t outputformat] DESCRIPTION
json_xs converts between some input and output formats (one of them is JSON). The default input format is "json" and the default output format is "json-pretty". OPTIONS
-v Be slightly more verbose. -f fromformat Read a file in the given format from STDIN. "fromformat" can be one of: json - a json text encoded, either utf-8, utf16-be/le, utf32-be/le storable - a Storable frozen value storable-file - a Storable file (Storable has two incompatible formats) clzf - Compress::LZF format (requires that module to be installed) yaml - YAML (avoid at all costs, requires the YAML module :) eval - evaluate the given code as (non-utf-8) Perl, basically the reverse of "-t dump" -t toformat Write the file in the given format to STDOUT. "toformat" can be one of: json, json-utf-8 - json, utf-8 encoded json-pretty - as above, but pretty-printed json-utf-16le, json-utf-16be - little endian/big endian utf-16 json-utf-32le, json-utf-32be - little endian/big endian utf-32 storable - a Storable frozen value in network format storable-file - a Storable file in network format (Storable has two incompatible formats) clzf - Compress::LZF format yaml - YAML dump - Data::Dump dumper - Data::Dumper Note that Data::Dumper doesn't handle self-referential data structures correctly - use "dump" instead. EXAMPLES
json_xs -t null <isitreally.json "JSON Lint" - tries to parse the file isitreally.json as JSON - if it is valid JSON, the command outputs nothing, otherwise it will print an error message and exit with non-zero exit status. <src.json json_xs >pretty.json Prettify the JSON file src.json to dst.json. json_xs -f storable-file <file Read the serialised Storable file file and print a human-readable JSON version of it to STDOUT. json_xs -f storable-file -t yaml <file Same as above, but write YAML instead (not using JSON at all :) lwp-request http://cpantesters.perl.org/show/JSON-XS.json | json_xs Fetch the cpan-testers result summary "JSON::XS" and pretty-print it. AUTHOR
Copyright (C) 2008 Marc Lehmann <json@schmorp.de> perl v5.14.2 2010-08-17 JSON_XS(1p)
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