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Top Forums Shell Programming and Scripting To print diamond asterisk pattern based on inputs Post 303037731 by Chubler_XL on Sunday 11th of August 2019 05:02:46 PM
Old 08-11-2019
Quote:
Originally Posted by wisecracker
Hi Chubler_XL...
AND finally are you sure it was my code you tested because the original version did NOT count the stars, I forgot to add it...
I was demonstrating how the original code we were asked to simplify in Post #1 works .
I believe this was indicated as doing what was required.


Here is a solution using dash. I make use of a function fill. fill's first argument is the total length of output required and the 2nd (optional) argument specifies the string to use (single space being the default).

As an example fill 3 gives 3 spaces, and fill 5 "AB" gives ABABA.

This function can be used to output a diamond in this fashion:
Code:
fill 3 ; fill 2 '* ' ; echo
fill 2 ; fill 4 '* ' ; echo
fill 1 ; fill 6 '* ' ; echo
fill 0 ; fill 8 '* ' ; echo
fill 1 ; fill 6 '* ' ; echo
fill 2 ; fill 4 '* ' ; echo
fill 3 ; fill 2 '* ' ; echo

And here is the full dash solution using this method:
Code:
#!/bin/dash

fill ()
{
    # fill string to width of count from string chars 
    #
    # usage:
    #      fill count [chars]
    #
    # if count is zero (or less) a blank string is output
    # chars defaults to a space
    #
    local width=$(( ($1) ))
    local str="${2:- }"

    while [ $width -gt 0 ]
    do
        while [ ${#str} -gt $width ]
        do
            str=${str%?}
        done
        width=$((width-${#str}))
        printf "%s" "$str"
    done
}

printf "Enter the mininum number: "
read MIN
printf "Enter the maximum number: "
read MAX

STARS=0
N=$MIN
while [ $N -le $((MAX*2-MIN)) ]
do
    A=$((N-MAX))
    W=$(($MAX-${A#-}))
    fill MAX-W ; fill W*2 '* ' ; echo
    STARS=$((STARS+W))
    N=$((N+1))
done
echo "Total stars: $STARS"


Last edited by Chubler_XL; 08-11-2019 at 06:19 PM..
This User Gave Thanks to Chubler_XL For This Post:
 

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