Hi arm,
Please be very careful when posting your code. When I tried to run your script with the data you supplied, the output I got was:
(Note that there is a space at the end of that output. The BRE that you supplied to your first sed has two spaces after the asterisk and there aren't any occurrences of two adjacent spaces in your sample input. So I don't see how the code you showed us could have produced the output you showed us.
Assuming that there is no more than one occurrence of that field in an input line, one might also try:
which might be a little bit faster since it doesn't have to process dozens of fields that don't match.
Note also that using cat and sed as input and output filters for awk is almost always a waste of system resources that will slow down your script and may also delay other things running on your system while your script is running.
This User Gave Thanks to Don Cragun For This Post:
I have a script that shows me the disk SPace used by different dir under my home dir:
#!/bin/ksh
cd /ednpdtu3/u01/pipe
p1=`df -g | tail -1 | tr -s " " | cut -d " " -f2`
echo "Total Disk Space of Home Dir is $p1 GB"
p2=`df -g | tail -1 | tr -s " " | cut -d " " -f3`
echo "Total Disk Space... (2 Replies)
Hi...
i need a script to remove the space before and after the operator like( / ).
Ex :
Input file
apple / manago
mango / fresh apple / fresh
Desired output:
apple/manago
mango/fresh apple/fresh
Note: betwee the desired operator space should be removed, between words do not remove... (3 Replies)
Hello
I have a file with data something like this in it :
texttexttext "text .lst" TEXT=" text "
texttexttext "moretext .lst" TEXT=" text "
Question is how do I get rid of space so that the files looks like this :
texttexttext "text.lst" TEXT="text"
texttexttext... (8 Replies)
Hi guys,
I am new to shell scripting and I have a small problem...If someone can solve this..that would be great
I am trying to form a XML by reading a flat file using shell scripting
This is my shell script
LINE_FILE1=`cat FLEX_FILE1.TXT | head -1 | tail -1`
echo... (1 Reply)
I created a awk state to calculate the number of success however when the query runs it has a leading zero. Any ideas on how to remove the leading zero from the calculation?
Here is my query:
cat myfile.log | grep | awk '{print $2,$3,$7,$11,$15,$19,$23,$27,$31,$35($19/$15*100)}'
02:00:00... (1 Reply)
Hi,
I have file which contains following lines
A| 965.|Mr.|35.45| 66.
B| 33.| a456.| 77.
The output should be
A|965|Mr.|35.45|66
B|33| a456.|77
Basically if a Number has space in prefix and . in suffix remove both.
So pattern could be if there is a | which has next two characters as... (1 Reply)
Hello,
I need help. I have xml file and there are one extra space on number <EpiReference>1 42345</EpiReference>. And of cource, the value change on every new file. I need remove space from that value what is in between <EpiReference> and </EpiReference>. How I can do that?
This are example... (9 Replies)
Discussion started by: Jopsulainen
9 Replies
LEARN ABOUT PLAN9
regexp
REGEXP(6) Games Manual REGEXP(6)NAME
regexp - regular expression notation
DESCRIPTION
A regular expression specifies a set of strings of characters. A member of this set of strings is said to be matched by the regular
expression. In many applications a delimiter character, commonly bounds a regular expression. In the following specification for regular
expressions the word `character' means any character (rune) but newline.
The syntax for a regular expression e0 is
e3: literal | charclass | '.' | '^' | '$' | '(' e0 ')'
e2: e3
| e2 REP
REP: '*' | '+' | '?'
e1: e2
| e1 e2
e0: e1
| e0 '|' e1
A literal is any non-metacharacter, or a metacharacter (one of .*+?[]()|^$), or the delimiter preceded by
A charclass is a nonempty string s bracketed [s] (or [^s]); it matches any character in (or not in) s. A negated character class never
matches newline. A substring a-b, with a and b in ascending order, stands for the inclusive range of characters between a and b. In s,
the metacharacters an initial and the regular expression delimiter must be preceded by a other metacharacters have no special meaning and
may appear unescaped.
A matches any character.
A matches the beginning of a line; matches the end of the line.
The REP operators match zero or more (*), one or more (+), zero or one (?), instances respectively of the preceding regular expression e2.
A concatenated regular expression, e1e2, matches a match to e1 followed by a match to e2.
An alternative regular expression, e0|e1, matches either a match to e0 or a match to e1.
A match to any part of a regular expression extends as far as possible without preventing a match to the remainder of the regular expres-
sion.
SEE ALSO awk(1), ed(1), sam(1), sed(1), regexp(2)REGEXP(6)