Hi Team,
I'm new to unix and i have a requirement to copy or move files from one directory to another based on current date mentioned in the .zip file name. Note that i need to copy only the recent zip file. please help me with the code
i tried the code as:
Code:
#! /usr/bin/sh
find /var/tmp/NewFile/TestM/ -name '*.txt' -mtime 0 | while read FILE
do
echo "Found file $FILE"
done
But, this gives only if the file is found or not but i need to copy as well if zip file is found.
Data :
Code:
-rw-rw-rw- 1 user user 1697 Jul 02 09:57 file_02072019.txt
-rw-rw-rw- 1 user user 103 Jul 02 09:57 file_02072019.zip
Moderator's Comments:
edit by bakunin: please use CODE-tags for code, data and terminal output. Thank you.
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Discussion started by: b.saipriyanka
1 Replies
LEARN ABOUT MOJAVE
zipsplit
zipnote(1) General Commands Manual zipnote(1)NAME
zipsplit - split a zipfile into smaller zipfiles
SYNOPSIS
zipsplit [-t] [-i] [-p] [-s] [-n size] [-r room] [-b path] [-h] [-v] [-L] zipfile
ARGUMENTS
zipfile Zipfile to split.
OPTIONS -t Report how many files it will take, but don't make them.
-i Make index (zipsplit.idx) and count its size against first zip file.
-n size
Make zip files no larger than "size" (default = 36000).
-r room
Leave room for "room" bytes on the first disk (default = 0).
-b path
Use path for the output zip files.
-p Pause between output zip files.
-s Do a sequential split even if it takes more zip files.
-h Show a short help.
-v Show version information.
-L Show software license.
DESCRIPTION
zipsplit reads a zipfile and splits it into smaller zipfiles.
EXAMPLES
To be filled in.
BUGS
Does not yet support large (> 2 GB) or split archives.
SEE ALSO zip(1), unzip(1)AUTHOR
Info-ZIP
v3.0 of 8 May 2008 zipnote(1)
07-02-2019
