Simple awk question Post: 303036263

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Hi, Probably a very weak question.. but I have tried all I know.. BPC0001:ANNUL_49542 0.0108 -0.0226 -0.0236 0.0042 0.0033 -0.0545 0.0376 0.0097 -0.0093 -0.032 Control BPC0002:ANNUL_49606 0.0190 -0.0142 -0.0060 -0.0217 -0.0027 ...

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Hi, let's assume i have an output below: orgauser 23826 :E:Validity senerse 2096 senerse 2111 senerse 21585 senerse 21596 root 12653 -bash root 17262 root 17278 Some lines have not any string in their third column. I don't want to see those lines. i just want to see the lines...

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I have what a think is a simple question but I'm just a beginner in scripting. I'm my unix command line I run a date command that returns the following: Wed Apr 3 10:39:30 EDT 2013 How do I awk out the "10" only in awk? Or is awk the way to do it or is there a better way?

LEARN ABOUT DEBIAN

igawk

IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME

       igawk - gawk with include files

SYNOPSIS

       igawk [ all gawk options ] -f program-file [ -- ] file ...
       igawk [ all gawk options ] [ -- ] program-text file ...

DESCRIPTION

       Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).

       AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like

	      @include getopt.awk

       in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.

OPTIONS

       See gawk(1) for a full description of the AWK language and the options that gawk supports.

EXAMPLES

       cat << EOF > test.awk
       @include getopt.awk

       BEGIN {
	    while (getopt(ARGC, ARGV, "am:q") != -1)
		 ...
       }
       EOF

       igawk -f test.awk

SEE ALSO

       gawk(1)

       Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.

AUTHOR

       Arnold Robbins (arnold@skeeve.com).

Free Software Foundation					    Nov 3 1999								  IGAWK(1)

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LEARN ABOUT DEBIAN

igawk