06-13-2019
How to calculate the quarter end date according to the current date in shell script?
Hi,
My question is how to calculate the quarter end date according to the current date in shell script?
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DATE(1) General Commands Manual DATE(1)
NAME
date - print or set the date and time
SYNOPSIS
date [-qsu] [[MMDDYY]hhmm[ss]] [+format]
OPTIONS
-q Read the date from stdin
-s Set the time (implicit for -q or a date string)
-u Print the date as GMT
-t Use this number of seconds instead of current time
EXAMPLES
date # Print the date and time
date 0221921610 # Set date to Feb 21, 1992 at 4:10 p.m.
DESCRIPTION
With the -q flag or a numeric argument, date sets the GMT time and date. MMDDYY refers to the month, day, and year; hhmmss refers to the
hour, minute and second. Each of the six fields must be exactly two digits, no more and no less. date always display the date and time,
with the default format for the system. The -u flag request GMT time instead of local time. A format may be specified with a + followed
by a printf-like string with the following options:
%% % character
%A Name of the day
%B Name of the month
%D mm/dd/yy
%H Decimal hour on 2 digits
%I Decimal hour modulo 12 on 2 digits
%M Decimal minute on 2 digits
%S Decimal seconds on 2 digits
%T HH:MM:SS
%U Decimal week number, Sunday being first day of week
%W Decimal week number, Monday being first day of week
%X Same as %T
%Y Decimal year on 4 digits
%Z Time Zone (if any)
%a Abbreviated name of the day
%b Abbreviated name of the month
%c Appropriate date & time (default format)
%d Decimal day of the month on 2 digits
%e Same as %d, but a space replaces leading 0
%h Same as %b
%j Decimal dey of the year on 3 digits
%m Decimal month on 2 digits
%n Newline character
%p AM or PM
%r 12-hour clock time with AM/PM
%s Number of seconds since the epoch
%t Tab character
%w Decimal day of the week (0=Sunday)
%x Same as %D
%y Decimal year on 2 digits
SEE ALSO
time(2), ctime(3), readclock(8).
DATE(1)