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Top Forums UNIX for Beginners Questions & Answers Print Line as per the dependent sequence in shell script. Post 303035939 by RudiC on Monday 10th of June 2019 06:18:17 AM
Old 06-10-2019
Quote:
Originally Posted by krishnaswarnkar
Hi Rudic ,

Checked with your reply but its giving the same output .
No, it suppresses lines that don't have a dependency met.
Quote:
...
For line "1836 25000 01052019 BH90P.TEMP.DA1836.FTP W 1836/24000;1801/24000;2248/24000"
Waiting for Value is "1836/24000;1801/24000;2248/24000" so we know the "1836 24000" is already in sequence before this job but "1801 24000" and "2248 24000" somewhere later in the so its necessary put those before this in sequence and also check their waiting for value as well ...
Do you mean you need ALL dependencies met? Why not say so? What would the desired output look like (small but representative sample)?


Quote:
Its like a Once job having multiple dependency but i want to arrange them in sequence ...
What do you mean?
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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