Just want to learn how these are read into array but I don't seem to get it right what do I go wrong?
Below is the sample
Thanks
input
1 2 3 4
5 6 7 8
9 1 2 3
4 5 6 7
#!/usr/bin/perl
open (InFILE,"input");
while (<InFILE>) {
@ar = split ; (5 Replies)
Hye all,
I would like some help with reading in a file in which the data is seperated by commas. for instance:
input.dat:
1,2,34,/test
for the above case, the fn. will store the values into an array -> data as follows:
data = 1
data = 2
data = 34
data = /test
I am trying to write... (5 Replies)
Dear Friends,
I am doing a sh shell script , But I dont have any idea how to read value from user Keyboard and store them to an array .. Is it possible or not I am not also sure in sh shell script ?
EX:-
#! /bin/sh
read DATA
echo "DATA -" $DATA
echo "DATA -" $DATA
echo "DATA... (7 Replies)
how do we read input from a user
e.g i want to ask a user to enter 6 sets of numbers
how do i control information from the user?
i have this.......
#!/bin/bash
echo "Please enter six numbers"
read number
echo $number >> file1
but this stops after the first number..how can i... (2 Replies)
Hi all,
I wrote a script that reads inputs from user and store in array named "input". The number of elements in the array is not fixed - determined only after user exit the while loop that reads the array values :
x=1
echo "Enter first value"
read input
while } != "exit" ]
do
... (1 Reply)
I am writing a script where it uses yum to install. I need to read the user input for yum ie "y or n". If the user types "y", the script should continue running. If the user types "n" then the whole script should be terminated.
line1
line2
yum install package
line3
line4
From above,... (5 Replies)
I need some help with this code below, i doesnt know why it will run twice with my function, but my function only got if else, any other way that can read line and put into array?
while read line; do
read -A array <<<$line
n=${#array}
for ((i=1;i<$n;i++)); do
print... (1 Reply)
Hi all,
I have a little problem with my shell script (reading user input, save user input to variable, invisible characters in the log file :()
printf "1. What's your file path?"
/path/to/my/file
read -e FILE
I have invisible characters in my log file (e.g. <ESC> or ^G) when I'm... (3 Replies)
I am not able to capture the user input in this script(bash).There is prompt for user input.Could some one help me capture user input while reading afile?
while read line
do
echo "$i"
path1=$line
path2=`echo $line|sed s/new_dir/old_dir/`
echo "Do you want to replace?";... (4 Replies)
I have a process that requires me to read data from huge log files and find the most recent entry on a per-user basis. The number of users may fluctuate wildly month to month, so I can't code for it with names or a set number of variables to capture the data, and the files are large so I don't... (7 Replies)
Discussion started by: rbatte1
7 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)