Date Vadidation in YYYY-MM-DD
Hi ,
Please, Help me in validating given date that is passed in arg as YYYY-MM-DD.
It should cover
check 1 <= DD <= 31 and 1 <= MM <= 12
for each mm check 1 <=DD<= {28,30,31} (depending)
for someYYYY and MM== 02 check 1 <= dd <= 29
I the... (1 Reply)
I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix
my script will generate text file which have two fields
one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Hello,
I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
read line
... (4 Replies)
I have this code to compare columns 1 and 10 between file1 and file 2 and give me all records that match column 1 but dont match column 10
However column 10 is date format mm/dd/yy and awk cant read it and compare ...i tried
awk < file1 -F~ '{print $10}'
and it gave blank screen
Is... (1 Reply)
could you please help be on the below code ..
Requirement is when i pass the parameter(for below 2) i should get current time -2 hours in the format :wall:..
cur_dt=`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID -P $PASSWD -h -C"select getdate()" | sed '2d'`
pr_dt="`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID... (2 Replies)
Hi I have a problem with Date format in my code.
1st I am trying to convert today's date to yesterday's using
YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'`
And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
I've seen a lot of posts on this and have tried the following:
echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";'
But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY.
I am using bash and don't know... (4 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
Discussion started by: Roozo
3 Replies
LEARN ABOUT MOJAVE
colrm
COLRM(1) BSD General Commands Manual COLRM(1)NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO awk(1), column(1), cut(1), paste(1)HISTORY
The colrm command appeared in 3.0BSD.
BSD August 4, 2004 BSD