Hi,
I'm quite new to scripting and I want to modify following line of an existing script:
MYVAR=`subst |grep 'L:\\\:' | sed -e 's/.*\\\//'`;
What I have to do is to use the content of a variable instead of the constant expression 'L:\\\:' as the grep string to be matched.
Assuming I already... (5 Replies)
Hi
I am trying to write a function that needs to be able to assign the last run shell command to a variable. The actual command string itself not the exit code of the command.
I am using the bash command recall ability to do this as follows:
alias pb='ps | grep ash' ... (3 Replies)
Hi Friends...
Please assist me to assign the result of a SQL query that results two column, to two variables.
Pls find the below code that I write for assigning one column to one variable. and please correct if anything wrong..
#! /bin/sh
no='
sqlplus -s uname/password@DBname... (4 Replies)
Hi,
I am new to UNIX Scripting. I have been trying to use the CUT command to retrieve part of the header from a file and assign it to a variable. I have tried searching a lot, but I am still unsuccessful.
Sample Header: HJAN BALANCE 20090616
I need to retrieve the date here, which always... (10 Replies)
Hi ,
I would like to assign command (with pipe) output to a variable. The code is as follows. The goal of the code is to get the last folder folder with a particular name pattern.
myDate=`ls | grep 2009 | tail -1`
echo "myDate=" $myDate
However, in the presence of the pipe, the code... (3 Replies)
Code
set -x
STATUS="0"
echo $STATUS
for i in `ls -ltr Report*|awk '{ print $9 }'`
do
if
then
flg = "`head -1 "$i" |cut -c 31-33`"
echo `head -1 "$i" |cut -c 31-33`
echo $flg
if
then
echo "having Fun"
STATUS="2"
else
echo "no Fun"
fi
fi (2 Replies)
Hi,
I have the following command that lists all the .o files from all the directories except of vwin (which I don't want it)
for i in `ls -d */*.o|awk '$0 !~ "vwin"'`; do echo $i; done
The result is something like that
dir1/file1.o
dir1/file2.o
dir2/file3.o
etc.
So, I want to create a... (9 Replies)
Hello All,
Hope you're doing well !
I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted.
header_date_14=$(m_dump... (8 Replies)
In the else of the main if condition .
else
set lnk = $(readlink -f <path> | cut -d '/' -f7)
echo "$lnk"
if ]
When I run the above on command line , the execution seems to be fine and I get the desired output. But when I try to assign it to a variable within a loop... (12 Replies)
Discussion started by: sankasu
12 Replies
LEARN ABOUT PLAN9
ssh-argv0
SSH-ARGV0(1) BSD General Commands Manual SSH-ARGV0(1)NAME
ssh-argv0 -- replaces the old ssh command-name as hostname handling
SYNOPSIS
hostname | user@hostname [-l login_name] [command]
hostname | user@hostname [-afgknqstvxACNTX1246] [-b bind_address] [-c cipher_spec] [-e escape_char] [-i identity_file] [-l login_name]
[-m mac_spec] [-o option] [-p port] [-F configfile] [-L port:host:hostport] [-R port:host:hostport] [-D port] [command]
DESCRIPTION
ssh-argv0 replaces the old ssh command-name as hostname handling. If you link to this script with a hostname then executing the link is
equivalent to having executed ssh with that hostname as an argument. All other arguments are passed to ssh and will be processed normally.
OPTIONS
See ssh(1).
FILES
See ssh(1).
AUTHORS
OpenSSH is a derivative of the original and free ssh 1.2.12 release by Tatu Ylonen. Aaron Campbell, Bob Beck, Markus Friedl, Niels Provos,
Theo de Raadt and Dug Song removed many bugs, re-added newer features and created OpenSSH. Markus Friedl contributed the support for SSH
protocol versions 1.5 and 2.0. Jonathan Amery wrote this ssh-argv0 script and the associated documentation.
SEE ALSO ssh(1)Debian Project September 7, 2001 Debian Project