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Top Forums Shell Programming and Scripting Sorting the contents of a variable Post 303034987 by jgt on Friday 10th of May 2019 12:13:22 PM
Old 05-10-2019
Sorting the contents of a variable

i want to reduce the OPTIONS variable which is a list of email addresses to just the unique entries. The following works, but, i would like to accomplish it without using the temporary file (dest.txt)



Code:
$echo $OPTIONS                         
a b c A B D                                         
$cat clean                             
#!/usr/bin/bash                                     
n=$#                                                
i=1                                                 
cat /dev/null >/usr/spool/lp/temp/dest.txt          
while [ $i -le $n ]                                 
do                                                  
        c=$(echo $1 |tr "[:upper:]" "[:lower:]" )   
        echo $c>>/usr/spool/lp/temp/dest.txt        
        shift                                       
        let i=$i+1                                  
done                                                
sort -u </usr/spool/lp/temp/dest.txt                
                                                    
$ OPTIONS1=$(./clean $OPTIONS)          
$ echo $OPTIONS1                        
a b c d                                             
$

 

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STRCAT(3)						     Linux Programmer's Manual							 STRCAT(3)

NAME
strcat, strncat - concatenate two strings SYNOPSIS
#include <string.h> char *strcat(char *dest, const char *src); char *strncat(char *dest, const char *src, size_t n); DESCRIPTION
The strcat() function appends the src string to the dest string, overwriting the null byte ('') at the end of dest, and then adds a ter- minating null byte. The strings may not overlap, and the dest string must have enough space for the result. The strncat() function is similar, except that * it will use at most n characters from src; and * src does not need to be null-terminated if it contains n or more characters. As with strcat(), the resulting string in dest is always null-terminated. If src contains n or more characters, strncat() writes n+1 characters to dest (n from src plus the terminating null byte). Therefore, the size of dest must be at least strlen(dest)+n+1. A simple implementation of strncat() might be: char* strncat(char *dest, const char *src, size_t n) { size_t dest_len = strlen(dest); size_t i; for (i = 0 ; i < n && src[i] != '' ; i++) dest[dest_len + i] = src[i]; dest[dest_len + i] = ''; return dest; } RETURN VALUE
The strcat() and strncat() functions return a pointer to the resulting string dest. CONFORMING TO
SVr4, 4.3BSD, C89, C99. SEE ALSO
bcopy(3), memccpy(3), memcpy(3), strcpy(3), string(3), strncpy(3), wcscat(3), wcsncat(3) COLOPHON
This page is part of release 3.27 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/. GNU
2010-09-20 STRCAT(3)
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