05-10-2019
Yes this will replace any year(If year is less than 2000 then prefix 19) and you can pass csv file to awk
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1. Shell Programming and Scripting
Hi all
Wonder if you can help , I have a comma delimited file where the 13th to the 31st character of each line is populated by the date and time."2004-07-21 09:39:06"
16-5-141551,2004-07-21 09:39:06,8815
22-5-340394,2004-07-22 09:39:41,8001
22-5-340433,2004-07-23 09:42:20,1701
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2. Shell Programming and Scripting
$ cat log.txt
Name Age Sex Lcation nfld alias xsd
CC 25 M XYZ asx KK Y
BB 21 F XAS awe SS N
SD 21 M AQW rty SD A
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dear all,
I'm trying to use Awk to eliminate the last two characters from the first column in a file. This two characters are "-1" and I need to eliminate them from each row that I have in the files. The files have two columns and look like:
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ID_3787-1 4
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4. Shell Programming and Scripting
Hi,
I need some unix command to replace the following thing.
cat test.dat
1234|test|8/19/2009|8/20/2009|test
1234|test|8/9/2009|8/21/2009|test
1234|test|8/1/2009|8/2/2009|test
after processing
1234|test|08/19/2009|08/20/2009|test
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5. Shell Programming and Scripting
Hi
cat test.txt
H|123|341|567|asfg
D|dfg|trtyy|errt
D|ert|frty|wer
Here I need to replace the third column value with 100 of the first record only and while printing I need to print the full file content also..I am expecting a result like this
H|123|100|567|asfg
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i have a file in the gz format , the content of the file is as follow.
gzcat f1.gz
# 1.name
# 2.location
# 3.age
# 4.dob
.
.
.
.
.
.
.
.
.
# 43.hobbies
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hi i have sample data
a,b,c,d,e,g h http://mysite.xyx
z,b,d,f,e,s t http://123124#
a,b,c,i,m,nothing
d,i,j,e,w,nothing
output expected is
a,b,c,d,e,http://mysite.xyx
z,b,d,f,e,http://123124#
a,b,c,i,m,nothing
d,i,j,e,w,nothing
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Hi All,
I need to extract a position in the file and multiple the value by 1000 and the replace it .
Original
0010001200084701217637306521200000000000010010000000 ---> 000847 * 1000
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Hello.
A find command return a list of file.
For each fileReplace the content starting with the first "§" (of two) ending with last "ɸ" (of two), regardless of the content ( five lines )
by the following content (exactly) :
§2019_08_23§ #
# ... (8 Replies)
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CAL(1) User Commands CAL(1)
NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS
-1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)