i have a file with 2 columns. i want to calculate the average of column 1 based on the values of column 2. here's how the file looks like. i want to calculate the sums of numbers corresponding to 1 and then calculate the average. same for numbers corresponding to zero. any help with a code would be appreciated.
Last edited by RavinderSingh13; 05-06-2019 at 03:39 AM..
I've been trying all night to come up with a script that will take a file that contains job completion times like this as input:
18:30
17:45
16:39
18:01
17:50
...
and figure the Average completion time. I've tried several things, and I just can't seem to get it to figure correctly. I'm... (5 Replies)
Hi, I am in ksh88
I am trying to get the result of the calculation using 3 variables:
TOTAL
CAPACITY
and get the following error:
$DB_CAPACITY=(( $DB_SIZE * 100 / $TOTAL ))
ksh: syntax error: `((' unexpected
I cannot figure out what am I doing wrong... Thanks for any help -A (2 Replies)
Dear users,
I need your support, I have a file like this:
272134.548 6680572.715
272134.545 6680572.711
272134.546 6680572.713
272134.548 6680572.706
272134.545 6680572.721
272134.543 6680572.710
272134.544 6680572.715
272134.543 6680572.705
272134.540 6680572.720
272134.544... (10 Replies)
for i in `lsvg`
do
echo "VG Name:" $i
echo "Total VG Size:"
lsvg $i |grep "TOTAL PPs:" |awk '{print $7}' | cut -c2-
echo "Free VG Size:"
lsvg $i |grep "FREE PPs:" | awk '{print $7}' | cut -c2-
done
The PP Sizes are in MB. I like to have the sizes in GB.
Also, I like to have the... (14 Replies)
MRTG-LOGFILE(1) mrtg MRTG-LOGFILE(1)NAME
mrtg-logfile - description of the mrtg-2 logfile format
SYNOPSIS
This document provides a description of the contents of the mrtg-2 logfile.
OVERVIEW
The logfile consists of two main sections.
The first Line
It stores the traffic counters from the most recent run of mrtg.
The rest of the File
Stores past traffic rate averates and maxima at increassing intervals.
The first number on each line is a unix time stamp. It represents the number of seconds since 1970.
DETAILS
The first Line
The first line has 3 numbers which are:
A (1st column)
A timestamp of when MRTG last ran for this interface. The timestamp is the number of non-skip seconds passed since the standard UNIX
"epoch" of midnight on 1st of January 1970 GMT.
B (2nd column)
The "incoming bytes counter" value.
C (3rd column)
The "outgoing bytes counter" value.
The rest of the File
The second and remaining lines of the file contains 5 numbers which are:
A (1st column)
The Unix timestamp for the point in time the data on this line is relevant. Note that the interval between timestamps increases as you
progress through the file. At first it is 5 minutes and at the end it is one day between two lines.
This timestamp may be converted in OpenOffice Calc or MS Excel by using the following formula
=(x+y)/86400+DATE(1970;1;1)
(instead of ";" it may be that you have to use "," this depends on the context and your locale settings)
you can also ask perl to help by typing
perl -e 'print scalar localtime(x),"
"'
x is the unix timestamp and y is the offset in seconds from UTC. (Perl knows y).
B (2nd column)
The average incoming transfer rate in bytes per second. This is valid for the time between the A value of the current line and the A
value of the previous line.
C (3rd column)
The average outgoing transfer rate in bytes per second since the previous measurement.
D (4th column)
The maximum incoming transfer rate in bytes per second for the current interval. This is calculated from all the updates which have
occured in the current interval. If the current interval is 1 hour, and updates have occured every 5 minutes, it will be the biggest 5
minute transfer rate seen during the hour.
E (5th column)
The maximum outgoing transfer rate in bytes per second for the current interval.
AUTHOR
Butch Kemper <kemper@bihs.net> and Tobias Oetiker <tobi@oetiker.ch>
2.17.4 2012-01-12 MRTG-LOGFILE(1)