Creating an array that stores files to be called on. Post: 303034696

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Hi, Is it possible to create a dynamic array in shell script. I am trying to get the list of logfiles that created that day and put it in a dynamic array. I am not sure about it. help me New to scripting Gundu

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Hi all, i am quite fimiliar with shell scripting but i wouldn't regard myself as a semi professional at it. I am trying to create an array variable to read in 4 lines from a file using head and tail command in a pipeline and store each line into each array. I have done the scripting in unix...

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i want to create an array the array elements are populated depending upon the number of entries present in a data file The data file is created dynamically how to achieve the same thanks

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Creating an array to hold posix thread ids: Only dynamic array works

I am facing a strange error while creating posix threads: Given below are two snippets of code, the first one works whereas the second one gives a garbage value in the output. Snippet 1 This works: -------------- int *threadids; threadids = (int *) malloc (num_threads * sizeof(int)); ...

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#!/bin/ksh #export CLASSPATH=$CLASSPATH:~dialp/cso/classes:/opt/oracle/product/8.1.6/jdbc/lib/classes12.zip #export LD_LIBRARY_PATH=$LD_LIBRARY_PATH:/opt/oracle/product/8.1.6/lib DATE="`date '+%m%d%Y'`" PATH=.:$PATH export PATH town_name='123' town_name='123' town_name='345'...

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Problem with array and creating directories

I have an interesting requirement. I have declaried an array like :- arr=`find . ! -name "." | xargs -I {} echo {} | cut -c 2-${#}` Then i will try to access the array elements like :- i=0 for i in ${arr}; do Here comes the confusions, the array elements are basically dir and files stored...

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Hi gurus, I need to create arrays from variables, via a loop. The issue I have is with the array name creation. How do I use a variable to define an array? I want to do something like declare -a $H where $H is my loop variable. I then need to add items to each array I've created,...

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